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3 years ago

ASAP ANSWER PLEASE WILL MARK BRAINLIEST

Physics

1 answer:

lisov135 [29]3 years ago

6 0

Yes

Explanation:

It is a reasonable result obtained.

Error = true value - measured value

true value = 24.5

measured value = 24.2

Error = 24.5 - 24.2 = 0.3g

The error reported in the reading is 0.3g

The reason why we had a disparity in the figures obtained from this measurement is primarily due to some erroneous scale.

The mixture at the end of the day is a solution.

We are expected to have the same mass but due to experimental or some form of random error introduced, we noticed a difference.

The value obtained is quite logical as we only had a deviation of 0.3g.

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Error brainly.com/question/2764830

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At noon, ship A is 140 km west of ship B. Ship A is sailing east at 30 km/h and ship B is sailing north at 25 km/h. How fast (in

Luba_88 [7]

Answer:

The rate of change of distance between the two ships is 18.63 km/h

Explanation:

Given;

distance between the two ships, d = 140 km

speed of ship A = 30 km/h

speed of ship B = 25 km/h

between noon (12 pm) to 4 pm = 4 hours

The displacement of ship A at 4pm = 140 km - (30 km/h x 4h) =

140 km - 120 km = 20 km

(the subtraction is because A is moving away from the initial position and the distance between the two ships is decreasing)

The displacement of ship B at 4pm = 25 km/h x 4h = 100 km

Using Pythagoras theorem, the resultant displacement of the two ships at 4pm is calculated as;

r² = a² + b²

r² = 20² + 100²

r = √10,400

r = 101.98 km

The rate of change of this distance is calculated as;

r² = a² + b²

r = 101.98 km, a = 20 km, b = 100 km

$2r(\frac{dr}{dt} ) = 2a(\frac{da}{dt} ) + 2b(\frac{db}{dt} )\\\\r(\frac{dr}{dt} ) = a(\frac{da}{dt} ) + b(\frac{db}{dt} )\\\\101.98(\frac{dr}{dt} ) = 20(-30 ) + 100(25 )\\\\101.98(\frac{dr}{dt} ) = -600 + 2,500\\\\101.98(\frac{dr}{dt} ) = 1900\\\\\frac{dr}{dt} = \frac{1900}{101.98} = 18.63 \ km/h$