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8090 [49]
3 years ago
12

A 56 kg object is attached to a rope, which can be used to move the load vertically.

Physics
1 answer:
Sergio039 [100]3 years ago
8 0

Answer:

a) T=549.36N Upwards

b) T=448.56N Upwards

c) T=650.16N Upwards

Explanation:

The very first thing we can do to solve this problem is to draw a free body diagram we can use to analyze the situation (see attached picture).

On the diagram we can see there are only two forces acting on the object: the tension of the rope and the weight of the object itself.

a)

Since the object is moving at a constant speed, this means that its acceleration will be zero. So we can do a sum of forces like this:

\sum F=0

T-W=0

T=W

T=mg

T=(56kg)(9.81m/s^{2})

T=549.36N upwards

b)

For part b, since the object is accelerating downwards, we wil say that it's acceleration is negative, so a=-1.8m/s^{2}

so we can do a sum of forces again:

\sum F=ma

so

T-W=ma

T=ma +W

T=ma+mg

T=m(a+g)

and now we substitute:

T=(56kg)(-1.8 m/s^{2}+9.81 m/s^{2})

which yields:

T=448.56N upwards (in this particular case, the tension always goes upwards)

c)

Since the object is moving upwards, we can say that its acceleration will be positive, so a =1.8m/s^{2}

we can take the solved equation we got on the previous part of the problem, so we get:

T=m(a+g)

T =(56kg)(1.8 m/s^{2}+9.81 m/s^{2})

which yields:

T=650.16N upwards

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Answer:

it is a light receptor that generates nerve signals that are sent to the brain

Explanation:

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8 0
3 years ago
A truck traveling at a constant speed of 28 m/s passes a more slowly moving car. The instant the truck passes the car, the car b
choli [55]

Answer:

the velocity of car when it passes the truck is u = 16.33 m/s

Explanation:

given,

constant speed of truck  = 28 m/s

acceleration of car = 1.2 m/s²

passes the truck in 545 m

speed of the car when it just pass the truck = ?

time taken by the truck to travel 545 m

              time =\dfrac{distance}{speed}

              time =\dfrac{545}{28}

              time =19.46 s

velocity of the car when it crosses the truck

S = ut + \dfrac{1}{2}at^2

545= u\times 19.46 + \dfrac{1}{2} \times 1.2 \times 19.46^2

u = 16.33 m/s

the velocity of car when it passes the truck is u = 16.33 m/s

5 0
3 years ago
Two resistors, of R1 = 3.93 Ω and R2 = 5.59 Ω, are connected in series to a battery with an EMF of 24.0 V and negligible interna
son4ous [18]

Answer:

2.521 (A); 14.0924 (V)

Explanation:

more info in the attachment, the answers are marked with red colour.

4 0
3 years ago
What are two parts of an atom
seraphim [82]

Answer:

Nucleus And electron cloud

Explanation:

Hope this helps

7 0
3 years ago
A ball is thrown vertically upward with an initial velocity
ivolga24 [154]

Answer:

D

Explanation:

First we define our variables

V0=29.4

a=-9.8

V=0

We have to find the maximum displacement , which I will define as X

We use formula v^2=v0^2+2aX

All we do is substitute our values

0=29.4^2-19.6X

29.4^2=19.6X

X=29.4^2/19.6=44.1

5 0
2 years ago
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