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lys-0071 [83]
3 years ago
15

How many molecules is in this formula 3H2O​

Physics
1 answer:
jarptica [38.1K]3 years ago
7 0

Answer: There are 9 molecules.

Explanation: 3H2O has 6 hydrogen atoms and 3 oxygen atoms. Heres a diagram.

HHO + HHO + HHO = 3H2O

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Practice
marshall27 [118]

Answer:

In both cases the height is greater than 10.3 m

Explanation:

Pressure is defined by the relationship

       P = F / A

in this case the force is the weight of the two gases

       F = W = m g

If we use the definition of density

      ρ = m / V

      V = A h

      m = ρ A h

we substitute

       P = ρ g h

       h = \frac{P}{\rho g}

For this case the density of the gases is

       ρ' = 0.9 \rho_{water}

       h =\frac{P}{0.9 \ \rho_{water} g}

we calculate

     ρ’= 0.9 \rho_{water}

     h = 1 105 / (0.9 1000 9.8)

     h = 11.3 m

      ρ’= 0.8 \rho_{water}

       h = 1 105 / (0.8 1000 9.8

       h = 12.8 m

In both cases the height is greater than 10.3 m

4 0
3 years ago
A 0.500-kg mass suspended from a spring oscillates with a period of 1.36 s. How much mass must be added to the object to change
lord [1]

The mass that must be added is 0.628 kg

Explanation:

The period of a mass-spring system is given by

T=2\pi \sqrt{\frac{m}{k}}

where

m is the mass

k is the spring constant

For the initial mass-spring system in the problem, we have

m = 0.500 kg

T = 1.36 s

Solving for k, we find the spring constant:

k=(\frac{2\pi}{T})^2 m = (\frac{2\pi}{1.36})^2 (0.500)=10.7 N/m

In the second part, we want the period of the same system to be

T = 2.04 s

Therefore, the mass on the spring in this case must be

m=(\frac{T}{2\pi})^2 k =(\frac{2.04}{2\pi})^2 (10.7)=1.128 kg

Therefore, the mass that must be added is

\Delta m = 1.128 - 0.500 = 0.628 kg

Learn more about period:

brainly.com/question/5438962

#LearnwithBrainly

5 0
4 years ago
A spring has a 12 cm length. When a 200-g mass is hung from the spring, it extends to 27 cm. The hanging mass were pulled downwa
BartSMP [9]

Answer:

The equation of the time-dependent function of the position is x(t)=5\cos(8.08t)

(b) is correct option.

Explanation:

Given that,

Length = 12 cm

Mass = 200 g

Extend distance = 27 cm

Distance = 5 cm

Phase angle =0°

We need to calculate the spring constant

Using formula of restoring force

F=kx

mg=kx

k=\dfrac{mg}{x}

k=\dfrac{200\times10^{-3}\times9.8}{(27-12)\times10^{2}}

k=13.06\ N/m

We need to calculate the time period

Using formula of time period

T=2\pi\sqrt{\dfrac{m}{k}}

Put the value into the formula

T=2\pi\sqrt{\dfrac{0.2}{13.6}}

T=0.777\ sec

At t = 0, the maximum displacement was 5 cm

So, The equation of the time-dependent function of the position

x(t)=A\cos(\omega t)

Put the value into the formula

x(t)=5\cos(2\pi\times f\times t)

x(t)=5\cos(2\pi\times\dfrac{1}{T}\times t)

x(t)=5\cos(2\pi\times\dfrac{1}{0.777}\times t)

x(t)=5\cos(8.08t)

Hence, The equation of the time-dependent function of the position is x(t)=5\cos(8.08t)

8 0
3 years ago
If you toss a ball vertically upward in a uniformly moving train, it returns to its starting place. Will it do the same if the t
gogolik [260]

Answer:No

Explanation:

No

As the train is accelerating so train velocity will be more as compared to the ball  and thus will cover more distance as compared to the ball.

When the ball is thrown upward with some velocity, it also possesses the train velocity at the time of throwing but as time passes velocity of train increases due to acceleration of the train. This causes the ball to fall behind the point of launch.

3 0
4 years ago
A light plane must reach a speed of 33m/s for takeoff.how long a runway is needed if the the acceleration is 3.0m/s^2
Tanzania [10]

Remark

Always write down your givens and what you want to find. The formula you use for such questions will suggest itself if you do this.

Givens

a = 3.0 m/s^2

vi = 0  I presume that's that the question assumes.

vf = 33 m/s

You want d

Formula

vf^2 = vi^2 + 2*a*d

Solution

33^2 = 0^2 + 2 * 3 * d

1089 = 6*d

d = 1089/6

d = 181.5 meters

8 0
4 years ago
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