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strojnjashka [21]
3 years ago
7

When an object is pushed by a force and moves in the direction of the force, work is done on the object. The amount of work equa

ls the force times the distance (W = Fd). A small particle is pushed by a force of 2.6 × 10-4 newtons over a distance of 3.7 × 10-3 meters. How much work was done on the particle? Express the answer to the correct number of significant figures and in proper scientific notation. The force did × 10 newton-meters of work on the particle.
Chemistry
1 answer:
lora16 [44]3 years ago
3 0

Explanation:

workdone = force \times distance \\ W = (2.6 \times  {10}^{ - 4} ) \times (3.7 \times  {10}^{ - 3} ) \\ W = 9.62 \times  {10}^{ - 7}  \: joules

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4. How many atoms are in 32.6 g of Oxygen?
Natali5045456 [20]

Hey there!

Oxygen has a molar mass of 16. That means 16g of oxygen is 1 mole.

32.6 ÷ 16 = 2.0375 moles

We have 2.0375 moles.

There are 6.022 x 10²³ atoms in one mole.

2.0375 x 6.022 x 10²³

1.3 x 10²⁴

There are 1.3 x 10²⁴ atoms in 32.6 grams of oxygen.

Hope this helps!

7 0
3 years ago
Read 2 more answers
| A solution containing 4.48 ppm KMnO4 exhibits
Artist 52 [7]

Answer:

Molar absorptivity or molar extinction co-effecient = 2120.14 cm⁻¹M⁻¹

Explanation:

First convert Concentration from ppm inM or mol/l

⇒ Molar mass of KMnO₄ = 158.03 g

⇒ 4.48 ppm = 4.48 mg/l = 4.48 x 10⁻³ g/l

⇒ Molarity = \frac{4.48 X10^{-3} }{158.03X 1(lit)} = 2.83 x 10⁻⁵ molar

Absorbance (A) = - log(T)     ( T = % transmittance)

                          = - log(0.859)

                          = 0.06

According to Lambert Beer's law

     

                 ε = \frac{A}{C X l}

      or,      ε = \frac{0.06}{2.83 X 10^{-5}X1 cm }

      or,      ε = 2120.14 cm⁻¹M⁻¹

Where

    ε = Molar absorptivity

    A = absorbance

    C = Molar concentration of KMnO₄ solution

     l = length  

6 0
3 years ago
How are carrot, an amoeba, and a bacterium alike
sineoko [7]
<span>They should all be eukaryotic.</span>
4 0
3 years ago
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What are the types of connective tissue? Describe each type, and give an example of each.
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Answer:

he major types of connective tissue are connective tissue proper, supportive tissue, and fluid tissue. Loose connective tissue proper includes adipose tissue, areolar tissue, and reticular tissue.

Explanation:

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3 years ago
Find the no. Of electron involved in the electro deposition of 63.5g of cu from a solution of cuso4
sp2606 [1]
This is a redox reaction, meaning reduction-oxidation reaction. This represents the reaction in one side of the electrode in an electrolysis set-up. First, we find the oxidation number of Cu in CuSO4:

(ox. # of Cu)+ ox.# of S + 4(ox.# of oxygen) = 0
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CuSO4 ---> Cu + SO42-
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The stoichiometric equation would be 2 electrons per mole Copper. Copper has a molar mass of <span>63.5 g/mol. Then, it would only need 2 electrons.


</span>
8 0
3 years ago
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