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Furkat [3]
3 years ago
13

How can you store energy with a rubber band

Engineering
1 answer:
stellarik [79]3 years ago
3 0

Most obviously and effectively by stretching it.  Heating it up, lifting it up or throwing it across the room will all store a small amount of energy in it for variously short spans of time

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Convert the following indoor air quality standards, established by the U.S. Occupational Safety and Health Administration (OSHA)
sp2606 [1]
Wouldn’t this be science not engineering?
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3 years ago
20 points and brainliest is it A, B, C, D
andre [41]
I think its c maybe..
6 0
3 years ago
Read 2 more answers
A thick casting with a thermal diffusivity of 5 x 10-6 m2/s is initially at a uniform temperature of 150oC. One surface of the c
fredd [130]

Answer:

T_o = 141.81 ^0C

Explanation:

Given that;

Thermal diffusivity \alpha = 5 \times 10 ^{-6} m^2/s

Thermal conductivity k = 20 \ W/m.K

Heat transfer coefficient h = ( we are to assume the imposed surface temperature ) = 20 W/m².K

Initial temperature = 150 ° C = (150+273) K = 423 K

Then coolant temperature with which the casting is exposed to = 20° C = (20+273)K = 293 K

Time = 40 seconds

Length = 20mm = 0.02 m

The objective is to determine the  temperature at the surface  at a depth of 20 mm after 40 seconds.

Bi = \dfrac{hL}{k}

Bi = \dfrac{20*0.02}{20}

Bi == 0.02

\tau = \dfrac{\alpha t}{L^2}

\tau=  \dfrac{5*10^{-6 }* 40}{0.020^2}

\tau = 0.5

For a wall at 0.2 Bi

A_1 = 1.0311

\lambda _1 = 0.4328

Therefore;

\dfrac{T_o - T_{\infty}}{T_i - T_{\infty}}= A_1 e ^{-( \lambda_1^2 \ \tau)

\dfrac{T_o - 293 }{423 - 293}= 1.0311 \times e ^{-( 0.438^2 \times 0.5 )

\dfrac{T_o - 293 }{423 - 293}= 1.0311 \times e ^{-( 0.0959 )

\dfrac{T_o - 293 }{130}= 1.0311 \times 0.9085

\dfrac{T_o - 293 }{130}= 0.937

T_o - 293= 0.937 \times 130

T_o - 293= 121.81

T_o = 121.81+ 293

T_o = 414.81 \ K

T_o = (414.81 - 273)^0C

T_o = 141.81 ^0C

4 0
4 years ago
Chemical engineers determine how to transport chemicals.<br> O True<br> False
Anna35 [415]

Answer:

Chemical Engineers determine how to transport chemicals:

TRUE

6 0
2 years ago
Read 2 more answers
Which of the following persons is not exempt from the licensing provisions of the Professional Engineers Act?
Kobotan [32]

Answer:

Please find the answer in the explanation

Explanation:

An employee of a communications company under the jurisdiction of the Public Utilities Commission when prepáring plans for communication lines can be exempted from the licensing provisions of the Professional Engineers Act.

Being an employee of a communications company under the jurisdiction of the Public Utilities Commission is not a criterion for getting a license to be a professional engineer nor a prerequisite for getting the license to be a professional engineer

6 0
3 years ago
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