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2 years ago

WILL MARK THE BRAINLIEST pls help

Physics

2 answers:

Hatshy [7]2 years ago

7 0

Answer: i think both mirrors are used to reflect the beam of light.

Explanation:

gr 10 science right? im almost done the semester and i learnt this already so i think the best answer is the last one

il63 [147K]2 years ago

3 0

Answer:

I think B but im not sure

Explanation:

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The specific heat of a certain type of metal is 0.128 J/(g⋅∘C).0.128 J/(g⋅∘C). What is the final temperature if 305 J305 J of he

Makovka662 [10]

Answer:

45.3°C

Explanation:

Heat gained = mass × specific heat × increase in temperature

q = mC (T − T₀)

Given C = 0.128 J/g/°C, m = 94.0 g, q = 305 J, and T₀ = 20.0°C:

305 J = (94.0 g) (0.128 J/g/°C) (T − 20.0°C)

T = 45.3°C

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3 years ago

During adverse weather conditions such as rain or fog, drivers should take action accordingly by turning on their headlights, sl

xeze [42]

During adverse weather conditions such as rain or fog, drivers should take action accordingly by turning on their headlights, slowing down and increasing following distance. Adverse weather means that you are driving in difficult and dangerous conditions. Increasing following distance will help you to maintain safe driving and avoid tailgating.

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2 years ago

A meter stick A hurtles through space at a speed v = 0.25c relative to you, with its length aligned with the direction of motion

yaroslaw [1]

Answer:

$L_0\approx1.0328\ m$

Explanation:

Given:

relativistic length of stick A, $L=1\ m$

relativistic velocity of stick A with respect to observer, $v=0.25c=7.5\times 10^{7}\ m.s^{-1}$

Since the object is moving with a velocity comparable to the velocity of light with respect to the observer therefore the length will appear shorter according to the theory of relativity.

Mathematical expression of the theory of relativity for length contraction:

$L=\frac{L_0}{\gamma}$

where:

L = relativistic length

$L_0=$ original length at rest

$\gamma =$ Lorentz factor $=\frac{1}{\sqrt{1-\frac{v^2}{c^2} } }$

$\Rightarrow 1=\frac{L_0}{\frac{1}{\sqrt{1-\frac{(0.25c)^2}{c^2} } }}$

$L_0=\frac{1}{\sqrt{1-\frac{(0.25c)^2}{c^2} } }$

$L_0\approx1.0328\ m$

4 0

2 years ago

Describe the relationship between a moving objects mass and its kinetic energy

swat32

Kinetic energy is the energy of mass in motion, the kinetic energy that an object has is because of it's motion.Heavier objects that are moving have more kinetic energy than lighter ones.

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3 years ago

A 4.00-kg block hangs by a light string that passes over a massless, frictionless pulley and is connected to a 6.00-kg block tha

Anna007 [38]

Answer:

v = 2.82 m/s

Explanation:

For this exercise we can use the conservation of energy relations.

We place our reference system at the point where block 1 of m₁ = 4 kg

starting point. With the spring compressed

Em₀ = K_e + U₂ = ½ k x² + m₂ g y₂

final point. When block 1 has descended y = - 0.400 m

Em_f = K₂ + U₂ + U₁ = ½ m₂ v² + m₂ g y₂ + m₁ g y

as there is no friction, the energy is conserved

Em₀ = Em_f

½ k x² + m₂ g y₂ = ½ m₂ v² + m₂ g y₂ + m₁ g y

½ k x² - m₁ g y = ½ m₂ v²

v² = $\frac{k}{m_2} x^2 - 2 \frac{m_1}{m_2} \ g y$

let's calculate

v² = $\frac{180}{6.00} \ 0.300^2 - 2 \ \frac{4.00}{6.00} \ 9.8 \ (- 0.400)$

v² = 2.7 + 5.23

v = √7.927

v = 2,815 m / s

using of significant figures

v = 2.82 m/s

5 0

2 years ago