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2 years ago

MY PAPER IS DUE IN AN HOUR!!!

Physics

2 answers:

Doss [256]2 years ago

7 0

Answer:

Your kinetic energy is always proportional to the square of your speed,

no matter whether you're on a bicycle, a roller coaster, or a baby carriage.

The faster you're moving, the more kinetic energy you have.

Your potential energy doesn't depend on speed at all, only on height.

On a roller coaster, the minimum speeds are usually at the top of a hill

or a loop, so the potential energy would generally correspond to the

slowest speeds. But again, that's not because of the speed. It's because

of the height.

Explanation:

Delvig [45]2 years ago

6 0

Answer:

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Explanation:

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A student runs up a flight of stairs which info is not needed to calculate the rate of the student is doing work against gravity

NikAS [45]

Answer:

Explanation:

Given that a student runs up a flight of stairs which info is not needed to calculate the rate of the student is doing work against gravity A the height of the flight of stairs B the length of flight of stairs C the time taken to run up the stairs D the weight of the student

The rate of doing work is known as power.

Power = work done/time

Work done = energy = mgh

Since energy = mgh

Where mg = weight

And h = height

Time = time taken to run up the stairs.

Time, weight mg and height h will be needed while the Length of the flight is therefore not needed.

The correct answer is B.

8 0

3 years ago

A moving curling stone, A, collides head on with stationary stone, B. Stone B has a larger mass than stone A. If friction is neg

Kitty [74]

Answer:

The correct answer is option 'c': Smaller stone rebounds while as larger stone remains stationary.

Explanation:

Let the velocity and the mass of the smaller stone be 'm' and 'v' respectively

and the mass of big rock be 'M'

Initial momentum of the system equals

$p_i=mv+0=mv$

Now let after the collision the small stone move with a velocity v' and the big roch move with a velocity V'

Thus the final momentum of the system is

$p_f=mv'+MV'$

Equating initial and the final momenta we get

$mv=mv'+MV'\\\\m(v-v')=MV'.....i$

Now since the surface is frictionless thus the energy is also conserved thus

$E_i=\frac{1}{2}mv^2$

Similarly the final energy becomes

$E_f=\frac{1}{2}mv'^2+\frac{1}{2}MV'^2$ \

Equating initial and final energies we get

$\frac{1}{2}mv^2=\frac{1}{2}mv'^2+\frac{1}{2}MV'^2\\\\mv^2=mv'^2+MV'^2\\\\m(v^2-v'^2)=MV'^2\\\\m(v-v')(v+v')=MV'^2......(ii)$

Solving i and ii we get

$v+v'=V'$

Using this in equation i we get

$v'=\frac{v(m-M)}{(M-m)}=-v$

Thus putting v = -v' in equation i we get V' = 0

This implies Smaller stone rebounds while as larger stone remains stationary.

4 0

3 years ago

A 37 N block rests on a horizontal surface. The coefficients of static and kinetic friction between the surface and the block ar

Ne4ueva [31]

Answer:

The frictional force acting on the block is 14.8 N.

Explanation:

Given that,

Weight of block = 37 N

Coefficients of static = 0.8

Kinetic friction = 0.4

Tension = 24 N

We need to calculate the maximum friction force

Using formula of friction force

$f=\mu mg$

Put the value into the formula

$f=0.8\times37$

$f=29.6\ N$

So, the tension must exceeds 29.6 N for the block to move

We need to calculate the frictional force acting on the block

Using formula of frictional force

$f = \mu N$

Put the value in to the formula

$f=0.4\times37$

$f=14.8\ N$

Hence, The frictional force acting on the block is 14.8 N.

6 0

3 years ago

If a dog ran at 5 m/s how far would it run in 45 s

Virty [35]

Answer:

225 m//s

Explanation:

It ran 5m/s so 5x45=225

3 0

2 years ago

Read 2 more answers

The carbon cycle relies on producers and consumers to survive. What is the role of each in the carbon cycle?

LiRa [457]

ANSWER: (ROLE of Producers in the cycle:totake in carbon dioxide from the atmosphere during photosynthesis and release carbon dioxide during respiration,ROLE of Consumers:to contribute to the carbon cycle when they perform respiration and expel carbon dioxide into the atmosphere)
Hope this Helps SOMEONE!!
,Thank you

8 0

3 years ago