Answer:
0.35
Explanation:
According to Newton's second law;
\sum Fx = ma
Fm - Ff =ma
Fm is the moving force = Wsin theta
Fm = 4(9.8)sin55
Fm = 32.1N
Ff is the frictional force = nmgcos theta
Ff = n(4)(9.8)cos55
Ff = 22.48n
Acceleration a = 6.0m/s²
Substitute the given values into the formula and get the coefficient of friction
32.11-23.48n = 4(6)
32.11-24= 23.48n
8.11 = 23.48
n = 8.11/23.48
n = 0.35
Hence the coefficient of friction is 0.35
Answer:
Friction between the box and the floor is 25N to the left.
Explanation:
According to Newton's second law of motion, the net force acting on an object is equal to the produce between the object's mass and its acceleration:

where
m is the mass of the object
a is its acceleration
In this problem, we have two forces acting on the object:
- The applied force, F = 25 N, to the right
- The force of friction
, opposing the motion of the box, so to the left
So we can write the net force as

Also, we know that the box is moving at constant speed: this means its acceleration is zero, so

Therefore

WHich means:

And therefore,

which means that the force of friction is also 25 N.
After fertilization in the fallopian tube, It will take 6-12 days for the zygote to travel before arriving at the uterus.
<h3>What is a zygote?</h3>
A zygote is, generally speaking, a cell created by the fusion of two gametes; the growing person is created from such a cell.
It takes the zygote around 6–12 days following fertilization in the fallopian tube for the fertilized egg to travel to the uterus and attach to the uterus, a process known as implantation.
Hence It will take 6-12 days for the zygote to travel before arriving at the uterus.
To learn more about the zygote refer;
brainly.com/question/465851
#SPJ1
Hi there!

Use the equation:

Where m2 and v2 deal with the larger object, and m1 and v1 with the smaller object. Plug in the given values:
v2 = ?
m1 = 0.048 kg (converted)
m2 = 2.95
v1 = 391

