To solve this, we can use two equations.
t1/2 = ln 2 / λ = 0.693 / λ
where, t1/2 is half-life and λ is the decay constant.
t1/2 = 10 min = 0.693 / λ
Hence, λ = 0.693 / 10 min - (1)
Nt = Nο e∧(-λt)
Nt = amount of atoms at t =t time
Nο= initial amount of atoms
t = time taken
by rearranging the equation,
Nt/Nο = e∧(-λt) - (2)
From (1) and (2),
Nt/Nο = e∧(-(0.693 / 10 min) x 20 min)
Nt/Nο = 0.2500
Percentage of remaining nuclei = (nuclei at t time / initial nuclei) x 100%
= (Nt/Nο ) x 100%
= 0.2500 x 100%
= 25.00%
Hence, Percentage of remaining nuclei is 25.00%
Carbonic acid.............................................
Answer:
Not doubled
Explanation:
The equation below represent the ideal gases relationship
PV ÷ T = constant
Here
P denotes pressure,
V denotes volume,
T denotes temperature in degrees Kelvin
Now
20 ° c = 273 + 20
= 293 K
And,
40 ° c = 313 K
So,
V = Vo. 313 K ÷ 293 K = 1.07 Vo
So, the volume is NOT doubled.
In the case when the temperature would be determined in degrees celsius at 0 degrees so the volume would be zero
4 moles of sugar.
Explanation:
A mole is defined as the amount of a substance contained in Avogadro's number of particles 6.02 x 10²³.
1 mole of substance = 6.02 x 10²³. molecules
Given that;
the sample of sugar contains 1.505 x 10²³.molecules
The number of moles in this amount of sugar is 4 moles
Learn more:
Number of moles brainly.com/question/13064292
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