If the grams of acetic acid is given, we can use this to calculate for the mass percent acetic acid in the vinegar.
The formula is:
%acetic acid = (grams of acetic acid in vinegar)/ grams of vinegar x 100%
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Single Replacement and Double Replacement reactions
Answer:
The partial pressure of argon in the flask = 71.326 K pa
Explanation:
Volume off the flask = 0.001 
Mass of the gas = 1.15 gm = 0.00115 kg
Temperature = 25 ° c = 298 K
Gas constant for Argon R = 208.13 
From ideal gas equation P V = m RT
⇒ P = 
Put all the values in above formula we get
⇒ P =
× 208.13 × 298
⇒ P = 71.326 K pa
Therefore, the partial pressure of argon in the flask = 71.326 K pa
Answer:
14 solubility in 200 gram of water at 20 c
Explanation:
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