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3 years ago

How do Newton’s law of motion explain why it is important to keep the ice smooth on a hockey rink

Physics

2 answers:

Anna71 [15]3 years ago

6 0

Smooth ice reduces the unbalanced forces that would slow the hockey puck.

nikklg [1K]3 years ago

5 0

Answer:

The correct answer is "Smooth ice reduces the unbalanced forces that would slow down the hockey puck".

Explanation:

Newton's law of motion gives us a basis for understanding the behavior of action forces and reaction to a displacement situation.

Smooth ice reduces the unbalanced forces that would slow down the hockey disc, because if there were deformations in the ice there would be friction forces that would stop the movement making it difficult for the disc to move through the ice.

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You might be interested in

The absolute pressure below the surface of a freshwater lake is 3.51 x 10^5 Pa. At what depth does this pressure occur? Assume t

kupik [55]

The general formula for absolute pressure is:

$P_{total} = P_{atm} + (rgh)$

Where: $P_{total}$ = Absolute pressure
$P_{atm}$ = atmospheric pressure
r = density
g = $9.8 \frac{m}{{s^2}}$
h = depth

We can use this formula to derive our formula for h:

$P_{total} = P_{atm} + (rgh)$ transpose atmospheric pressure
$P_{total} - P_{atm}$ = $(rgh)$ transpose r and g

$P_{total}$ - $P_{atm}$
------------------------- = h
rg

Now let us input our given into our new formula:

3.52 x $10^{5}$ - 1.01 x $10^{5}$
---------------------------------------- = h
1.00 x $10^{3}$ x 9.8 $\frac{m}{ s^{2} }$

$\frac{2.51 x {10^5}}{9.8 x {10^3} \frac{m}{s^2}} = h$

$25.61 m = h$

6 0

3 years ago

Jeremy was asked to describe the impact of humans on the carbon cycle. He answered: "When people

zmey [24]

Answer:

Humans add carbon dioxide to the atmosphere when they burn fuel in factories and other biomass sources. Humans take in carbon from the food they eat from the soil and return it back to the soil through waste products and decomposition.

Explanation:

When humans add carbon into the atmosphere the main contributors are burning of substances like fuels and biomass and from eating.

6 0

3 years ago

romanna [79]

Answer:HERE IS YOUR ANSWER

THE POINTS ARE

IF WE PUT THE OBJECT BETWEEN THE FOCUS

AND THE POLE

THEN THE IMAGE FORMED WILL be MAGNIFIED

If that’s not what you are looking for, try this one:

For concave mirror the virtual image is formed when the object is kept in between the pole and the focus.

Given here the "size of the image" is twice to that of the object.

Hence, it is consider that the magnification is +2.

So, the magnification value is positive and the image formed will be "virtual and erect". Thus, the object should be kept in between the "pole and the focus" in concave mirror."

Explanation:

3 0

4 years ago

Read 2 more answers

Last week we investigated the black hole at the center of our galaxy, with massMX= 8.5×1036kg. An object whose size is on the or

swat32

Answer:

$d=2.38*10^{13}m$

Explanation:

We know the mass of the hole, so we define as,

$M_x= {8.5*10^{36}}$ kg

For which centripetal force is equal to gravitational force

$\frac{mv^2}{r}=\frac{GMm}{d^2}$

Angular velocity is equal to v/r,

$w^2r=\frac{6.67*10^{-11}*8.5*10^{36}}{d^2}$

As r=1 and w=1, we clear to d,

$d^2=5.6695*10^{26}$ m

$d=2.38*10^{13}m$

6 0

4 years ago

A boy throws a snowball straight up in the air with an initial speed of 4.50 ft/s from a position 4.00 ft above the ground. The

IgorC [24]

Answer:

a) 0.658 seconds

b) 0.96 inches

Explanation:

$v=u+at\\\Rightarrow 0=4.5-32.1\times t\\\Rightarrow \frac{-4.5}{-32.1}=t\\\Rightarrow t=0.14 \s$

Time taken by the ball to reach the highest point is 0.14 seconds

$s=ut+\frac{1}{2}at^2\\\Rightarrow s=4.5\times 0.14+\frac{1}{2}\times -32.1\times 0.14^2\\\Rightarrow s=0.315\ ft$

The highest point reached by the snowball above its release point is 0.315 ft

Total height the snowball will fall is 4+0.315 = 4.315 ft

$s=ut+\frac{1}{2}at^2\\\Rightarrow 4.315=0t+\frac{1}{2}\times 32.1\times t^2\\\Rightarrow t=\sqrt{\frac{4.315\times 2}{32.1}}\\\Rightarrow t=0.518\ s$

The snowball will reach the bank at 0.14+0.518 = 0.658 seconds after it has been thrown

$v=u+at\\\Rightarrow v=0+32.1\times 0.518\\\Rightarrow v=16.62\ ft/s$

$v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-16.62^2}{2\times -100\times 3.28}\\\Rightarrow s=0.42\ ft$

The snowball goes 0.5-0.42 = 0.08 ft = 0.96 inches

8 0

4 years ago