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vesna_86 [32]
4 years ago
9

The major intracellular positively charged electrolyte is

Physics
1 answer:
lianna [129]4 years ago
4 0

the answer is potassium.

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Calculate the (absolute) pressure at the bottom of a neighborhood swimming pool 30.0 m by 8.0 m whose uniform depth is 2.0 m. Th
Alika [10]

Answer:

Total pressure= 120945[Pa]

Force exerted = 29026800 [N] or 29.02*10^6 [N]

Explanation:

We know that the total pressure is the result of the sum of the atmospheric pressure plus the manometric pressure. The equation is:

Ptotal=Patm + Pman

In this problem we know the atmospheric pressure 101.325x10^3 [Pa], therefore we need to find the manometric pressure.

The manometric pressure in the bottom of the swimming pool depends only on the water column of water generated (depth of the swimming pool)

Pman = density*g*h

where:

density = density of the water 1000 [kg/m^3]

g= gravity [m/s^2]

h= column of water (meters)

replacing the values:

Pman= 1000 *9.81* 2 = 19620 [Pa]\\\\

The total pressure will be:

Ptotal= 101325+19620 = 120945 [Pa]\\\\

The force exerte on the bottom is defined by the following expression:

Pressure=Force/area\\\\Force= Pressure*Area\\\\Area = 30m*8m= 240 m^2Force= 120945*240\\Force= 29026800N or 2958 Ton

4 0
4 years ago
For sprinters running at 12 m/s around a curved track of radius 26 m, how much greater (as a percentage) is the average total fo
Snezhnost [94]

Answer:

114.86%

Explanation:

In both cases, there is a vertical force equal to the sprinter's weight:

Fy = mg

When running in a circle, there is an additional centripetal force:

Fx = mv²/r

The net force is found with Pythagorean theorem:

F² = Fx² + Fy²

F² = (mv²/r)² + (mg)²

F² = m² ((v²/r)² + g²)

F = m √((v²/r)² + g²)

Compared to just the vertical force:

F / Fy

m √((v²/r)² + g²) / mg

√((v²/r)² + g²) / g

Given v = 12 m/s, r = 26 m, and g = 9.8 m/s²:

√((12²/26)² + 9.8²) / 9.8

1.1486

The force is about 114.86% greater (round as needed).

5 0
3 years ago
If a car and a bowling ball were thrown off a 100 foot cliff at the same time, which would hit the ground first?
nirvana33 [79]
They would hit the ground at the same time. No matter the weight laws of physics.
8 0
3 years ago
A 10- kg ball starting from rest rolls down a 5 m tall smooth hill from one person to another person who is standing at the bott
olya-2409 [2.1K]

Answer: 3.13 m

Explanation:

Given

mas of the ball is m=10 kg

The ball rolls down a vertical distance of 5 m

Spring constant of spring is k=100\ N/m

Here, the potential energy of the ball converted into kinetic energy which in turn converts into elastic potential energy

\Rightarrow mgh=\frac{1}{2}kx^2\quad [\text{x=compression in the spring}]\\\\\Rightarrow 10\times 9.8\times 5=\frac{1}{2}\cdot 100\cdot x^2\\\Rightarrow x=\sqrt{9.8}\\\Rightarrow x=3.13\ m

Thus, the spring compresses by 3.13 m.

6 0
3 years ago
You drive for 5 hours at a speed of 70 km/hr. How far did you go?
zubka84 [21]

Answer:

350 miles

Explanation:

because multiply 70 times 5 and you will get 350

7 0
3 years ago
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