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4 years ago

The major intracellular positively charged electrolyte is

Physics

1 answer:

lianna [129]4 years ago

4 0

the answer is potassium.

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A 70 watt light bulb is run by a 120 v circuit. how many amps does it use

Marizza181 [45]

Current = Power/Voltage. 70W/120v= 0.583 Amps.

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4 years ago

NEED HELP!!!!!!!!!!!!!

raketka [301]

it would be 'B' because it speeds up reactions

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3 years ago

A 2.0-cm-diameter parallel-plate capacitor with a spacing of 0.50 mm is charged to 200 V?What is the total energy stores in the

Rama09 [41]

1) $1.11\cdot 10^{-7} J$

The capacitance of a parallel-plate capacitor is given by:

$C=\frac{\epsilon_0 A}{d}$

where

$\epsilon_0$ is the vacuum permittivity

A is the area of each plate

d is the distance between the plates

Here, the radius of each plate is

$r=\frac{2.0 cm}{2}=1.0 cm=0.01 m$

so the area is

$A=\pi r^2 = \pi (0.01 m)^2=3.14\cdot 10^{-4} m^2$

While the separation between the plates is

$d=0.50 mm=5\cdot 10^{-4} m$

So the capacitance is

$C=\frac{(8.85\cdot 10^{-12} F/m)(3.14\cdot 10^{-4} m^2)}{5\cdot 10^{-4} m}=5.56\cdot 10^{-12} F$

And now we can find the energy stored,which is given by:

$U=\frac{1}{2}CV^2=\frac{1}{2}(5.56\cdot 10^{-12} F/m)(200 V)^2=1.11\cdot 10^{-7} J$

2) 0.71 J/m^3

The magnitude of the electric field is given by

$E=\frac{V}{d}=\frac{200 V}{5\cdot 10^{-4} m}=4\cdot 10^5 V/m$

and the energy density of the electric field is given by

$u=\frac{1}{2}\epsilon_0 E^2$

and using

$E=4\cdot 10^5 V/m$ , we find

$u=\frac{1}{2}(8.85\cdot 10^{-12} F/m)(4\cdot 10^5 V/m)^2=0.71 J/m^3$

7 0

4 years ago

Mikes car can accelerate from 0 mph to 40mph in 5 seconds what is the acceeration of his car in miles per hour per second

Montano1993 [528]

40/5=8. His speed increases 8mph/second :)

8 0

3 years ago

Read 2 more answers

Please solve the Problem.

prisoha [69]

The scalar reading during the process is 170. 5 Newton

<h3>How to determine the scalar reading</h3>

force = mass × acceleration

Given the mass = 55kg

In finding the acceleration, use the first equation of motion

v = u + at

u = 0

t = 2s

v = 6.5 m/s

Substitute the values

6.5 = 0 + 2a, make 'a' the subject

a = 6. 5÷ 2 = 3. 1 m/s²

Substitute the value of 'm' and 'a' in the original equation

F = 55× 3.1 = 170. 5 Newton

Hence, the scalar reading during the process is 170. 5 Newton

Learn more about force here:

brainly.com/question/13164598

#SPJ1

7 0

2 years ago