The answer to your question is SMOOTH
Answer: industrial properties
Explanation:
The power plant listed by the agent falls under industrial property. An industria property is a property which is either used in manufacturing, rentage, warehousing, processing e.t.c.
in this case the plant Would be used in the generation of power which would be sold. so yes the property falls under the category
<span>Radius = 4.6 m
Time for one complete rotation t = 5.5 s.
Distance = 2 x 3.14 x R = 2 x 3.14 x 4.6 m = 28.888.
Velocity V = distance / time = 28.888 / 5.5 s = 5.25 m/s
Force exerted by cat Fc = mV^2 / R = (mx 5.25^2) / 4.6 m
Force of the cat Fc = 6m, m being the mass.
Normal force = Us x m x g = Us x m x 9.81 = Us9.81m
equating the both forces => Us9.81m = 6m => Us = 6 / 9.81 => Us = 0.6116
So coefficient of static friction = 0.6116</span>
Answer:
t all= 30h
Explanation:
In this problem the speed of the plane is constant, so we can use the equations of uniform rectilinear motion, the definition of average speed is the distance traveled between the time taken.
v = d / t
Let's calculate each distance
First part of the trip
v₁ = d₁ / t₁
d₁ = v₁ t₁
d₁ = 120 t₁
Second part of the trip
v₂ = d₂ / t₂
d₂ = v₂ t₂
d₂ = 180 t₂
Total trip
v₃ = d₃ / t₃
d₃ = v₃ t₃
d₃ = 170 t₃
The total travel distance is the sum of each distance and the total time is the initial time of 5 h plus the time of the second part (t2)
d₁ + d₂ = 170 t₃
120 5 + 180 t₂ = 170 (5 + t₂)
Let's solve
600 + 180 t₂ = 850 +170 t₂
t₂ (180 -170) = 850 - 600
10 t₂ = 250
t₂ = 25 h
Therefore, the total travel time is
t all= 5 +25 = 30h
