Answer
Give that,
mass of two student m = 3.10 kg
distance from the axis of the rotation is r = 1 m
angular speed ω = 0.754 rad /s
moment of inertia I = 3.10 kg m²
position from the rotation of the axis is r_1 = 0.29 m
Total moment of inertia I ' = I + 2 m r²
= 3.1 +2 x 3.1 x( 1)^2
= 9.3 kg m²
moment of inertia inward horizontally from the position of rotation axis is
I" = I + 2 m r^2
= 3.1 + 2 * 3.1 kg ( 0.29)^2
= 3.62 kg m^2
a ) new angular speed is ω_1 =
=
= 1.94 rad /s
b ) K.E before the system pulls weight inward is
c )K.E after the system pulls weight inward is
Answer:
Explanation:
Given
coefficient of kinetic friction
mass of locomotive=180,000 kg
v=10 m/s
deceleration provided by friction
Time taken to stop completely is
v=u+at
where v=final velocity
u=initial velocity
a=acceleration
t=510.20 s
Distance traveled during this point
s=2551.02 m
Answer:
she used force to swing her ball all way back
Explanation:
The period of a simple pendulum depends only on the length of the pendulum and the gravitational acceleration:
where L is the pendulum length and g the gravitational acceleration.
The problem says that Maya and the swing form a simple pendulum, so we can use this formula to calculate the period of Maya's motion, using the length of the swing (L=1.8 m):
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Answer:
June Mar Fajardo
plus he plays for Phillipines men's national basketball team
and baseball is my favorite team sport because everyone has a role no matter how big or small it is