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d1i1m1o1n [39]
3 years ago
12

An airplane is flying at an altitude of 2,910 m, has mass of 5,320 kg, and experiences a drag force of 530 N. How much force mus

t the engines exert in order for the airplane to accelerate at 4.10 m/s2?
21,300 N

22,300 N

22,000 N

12,500 N

Physics
1 answer:
bonufazy [111]3 years ago
8 0
<h3>Answer</h3>

option A)

21,300 N

<h3>Explanation</h3>

Given that,

mass of plan = 5320kg

altitude at which plan is flying = 2910m

drag force = 530N

<h3>Number of forces acting on airplane </h3><h3>1)</h3>

Downward Force

weight = mg

           = 5320(9.81)

           = 52189.2 N

<h3>2)</h3>

Lifting Force

<h3>3) </h3>

Force that push the airplane forward, thrust

<h3>4)</h3>

Force that opposes thrust, drag

Since plane is horizontal it means weight = lifting force, this balance out.

So, in order to calculate thrust which engines exert in order for the airplane to accelerate at 4.10 m/s²

<h3>Fnet=ma or ΣF = ma,</h3>

<em>where Fnet (or ∑F) is the net external force, </em>

<em />

<h3>Fnet = Thrust - frictionalForce(drag)</h3>

ma = T - f

5320(4.10) = T - 530

21812 = T - 530

21812 - 530 = T

T = 21282 N

T ≈ 21,300 N

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<h3>What do you mean by Magnetic field?</h3>

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Answer:

3 L

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 2 L

Initial pressure (P₁) = 0.75 atm

Final pressure (P₂) = 0.5 atm

Final volume (V₂) =?

Using the Boyle's law equation, the new volume (i.e final volume) of the Ne gas can be obtained as:

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Initial pressure (P₁) = 0.75 atm

Final pressure (P₂) = 0.5 atm

Final volume (V₂) =?

P₁V₁ = P₂V₂

0.75 × 2 = 0.5 × V₂

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3 years ago
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