Given the following choices;
A) less than your true weight, mg.
B) equal to your true weight, mg.
C) more than your true weight, mg.
D) could be more or less than your true weight, mg, depending on the value of the speed.
The answer is; C
This is due to G-force. These are the perception of the weight of an object that is accelerating against gravity. We experience 1 g force on the surface of the earth because the ground exerts an upward exertion against gravity preventing as from falling to the center of the earth.
Answer:
9) This is a case of deceleration
10)-0.8 ms-2
b) acceleration is the change in velocity with time
11)
a) 100 ms-1
b) 100 seconds
12) 10ms-1
13) more information is needed to answer the question
14) - 0.4 ms^-2
15) 0.8 ms^-2
Explanation:
The deceleration is;
v-u/t
v= final velocity
u= initial velocity
t= time taken
20-60/50 =- 40/50= -0.8 ms-2
11)
Since it starts from rest, u=0 hence
v= u + at
v= 10 ×10
v= 100 ms-1
b)
v= u + at but u=0
1000 = 10 t
t= 1000/10
t= 100 seconds
12) since the sprinter must have started from rest, u= 0
v= u + at
v= 5 × 2
v= 10ms-1
14)
v- u/t
10 - 20/ 25
10/25
=- 0.4 ms^-2
15)
a=v-u/t
From rest, u=0
8 - 0/10
a= 8/10
a= 0.8 ms^-2
Answer:
2.91 x 10¹² sec
Explanation:
d = distance of nearest star, Proxima Centauri = 4.3 ly = 4.3 x 9.46 x 10¹⁵ m
v = speed of new horizon probe = 14 km/hr = 14000 m/s
t = time taken for the new horizon probe to reach nearest star, Proxima Centauri = ?
Using the equation
d = v t
Inserting the values given
4.3 x 9.46 x 10¹⁵ = (14000) t
t = 2.91 x 10¹² sec
I'd say the answer to this on is d.Facts as they are using the temperatures in the graph and the temperatures are not just estimates
Answer:
Force A=-−2,697.75 N
Force B=13, 488.75 N
Explanation:
Taking moments at point A, the sum of clockwise and anticlockwise moments equal to zero.
25 mg-20Fb=0
25*1100g=20Fb
Fb=25*1100g/20=1375g
Taking g as 9.81 then Fb=1375*9.81=13,488.75 N
The sum of upward and downward forces are same hence Fa=1100g-1375g=-275g
-275*9.81=−2,697.75. Therefore, force A pulls downwards
Note that the centre of gravity is taken to be half the whole length hence half of 50 is 25 m because center of gravity is always at the middle
