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ryzh [129]
3 years ago
15

Please answer number12

Chemistry
1 answer:
densk [106]3 years ago
7 0
Hydrogen maybe but I don’t know for sure
You might be interested in
The majority of the elements essential to life are found in what part of the periodic table?
IRINA_888 [86]
The rows in the top third - This group consists of elements like Sodium, Magnesium, Potassium and Calcium on the right and Chlorine, Carbon, Nitrogen and Oxygen on the left.
Sodium and Chlorine are components of salt, a very important compound of our blood, essential for transferring electrical signals from the brain to the rest of the body and vice versa. Calcium is the building block of our bones, while Magnesium and potassium ensure proper functioning of our organs.

3 0
3 years ago
Onsider the reaction below.
mamaluj [8]

Answer:

3.14 moles of hydrogen are produced

Explanation:

This is because for every 1 molesof hydrogen are produced 2 moles of oxygen are produced. So we take 6.28 divide it by 2 and we wend up with 3.14.

8 0
2 years ago
A 232 mL cup of whole milk contains about 27 mg of cholesterol. Express the cholesterol concentration of the milk in kilograms p
son4ous [18]

Explanation:

Cholesterol concentration = 27 mg/ 232 mL

Change unit mg/ml to kg/m³

1 kg = 1000 g

1 g = 1000 mg

1 kg = 1000000 mg

1 kg = 10⁶ mg

10⁶ mg = 1 kg

1 mg = 10^-6 kg

m³ = 1000 L

1 L = 1000 mL

m³ = 1000000 mL

m³ = 10⁶ mL

10⁶ mL = m³

1 mL = 10^-6 m³

Cholesterol concentration = 27 mg/ 232 mL

27 × 10^-6 kg/ 232 × 10^-6 m³

= 27/232 kg/m³

6 0
3 years ago
Show the calculation of the mole fraction of each gas in a 1.00 liter container holding a mixture of 8.65 g of CO2 and 4.32 g of
Vlad1618 [11]

Answer:

0.745 and 0.245

Explanation:

Mole fraction (χ) is  the number of moles of a component divided by the total number of moles in a mixture.  

We must calculate the moles of each component.  

Let CO₂ be Gas 1 and SO₂ be Gas 2.

1. Calculate the moles of each gas.

\text{n} _{1} = \text{8.65 g} \times \dfrac{\text{1 mol}}{\text{44.01 g}} = \text{0.1965 mol}\\\\\text{n} _{2} = \text{4.32 g} \times \dfrac{\text{1 mol}}{\text{64.06 g}} = \text{0.067 44 mol}

2. Calculate the total moles.

n_{\text{tot}} = \text{n}_{1} + \text{n}_{2} = \text{0.1965 mol} +\text{0.067 44 mol} = \text{0.2640 mol}

3. Calculate the mole fraction of each component

\chi_{1} =\dfrac{0.1965}{0.2640} = \mathbf{0.745}\\\\\chi_{2} =\dfrac{0.06744}{0.2640} = \mathbf{0.255}

6 0
3 years ago
In a plant, 1500kg of nitrogen oxide is consumed per day to produce 1,500 kg of nitrogen per day. What is the prevent yield?
slavikrds [6]

Answer:

65.21 percent

Explanation:

We are to find the percentage yield

We have this equation,

2no+o2 -->2no2

Such that 1500 kilograms/30grams

= Mno2/46

=1500/30 = mno2/46

We cross multiply from here

1500x46 = 30xMnO2

69000 = 30Mno2

69000/30 = MnO2

2300 = Mno2

The percentage yield would be

1500/2300 *100

= 0.6521 x 100

= 65.21%

This answers the question

5 0
3 years ago
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