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Furkat [3]
3 years ago
14

ASAP, NO TROLLS 20 points!!!!

Chemistry
2 answers:
MA_775_DIABLO [31]3 years ago
6 0

Answer:

1.- Chemical change

2.- Because the atoms in the image are tranformed into a new molecule

3.- Yes, it does

4.- Due to the amount of atoms are the same both in products and reagents

Explanation:

Fed [463]3 years ago
6 0

Answer:

1.- Chemical change

2.- Yes it does ,because the atoms in the image are transformed into a new molecule

3.- Yes, it does because energy is not being created or destroyed

4.- Due to the amount of atoms are the same both in products and reagents

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photoshop1234 [79]
D. 0.2 M

The concentration of a solution is basically the ratio of the solute present to the solvent in the solution. This is an intrinsic property, independent of the amount of solution that is present. A similar example is that of density. No matter the size of a sample, the density and concentration of that sample remain constant.
3 0
3 years ago
Calculate the ratio of effusion rates of cl2 to f2 .
WINSTONCH [101]
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6 0
3 years ago
The energy required to remove an electron from a neutral atom is known as its:
Otrada [13]

Answer:

Ionization energy

Explanation:

4 0
3 years ago
How many grams of water can be produce from the complete reaction of excess nitric acid and 33.2 mL of 0.245 M lithium hydroxide
Mariulka [41]

Mass of water produced : 0.146 g

<h3>Further explanation</h3>

Given

33.2 mL of 0.245 M lithium hydroxide

Required

mass of water

Solution

Reaction

HNO₃ (aq) + LiOH (aq) → H₂O (l) + LiNO₃ (aq)

mol LiOH :

= M x V

= 0.245 x 33.2 ml

= 8.134 mmol

From the equation, the mol ratio of HNO₃ : H₂O = 1 : 1, so mol H₂O = 8.134 mmol

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= mol x MW

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= 0.146 g

3 0
3 years ago
Write the expression for the equilibrium constant Kp for the following reaction. (Enclose pressures in parentheses and do NOT wr
Liono4ka [1.6K]

Answer and Explanation:

For the following balanced reaction:

PCl₅(g) ↔ PCl₃(g) + Cl₂(g)

We can see that all reactants and products are gases, so it is an homogeneous equilibrium. The expression for the equilibrium constant Kp can be written from the partial pressures (P) of reactants and products as follows:

Kp=\frac{(P PCl_{3})(P Cl_{2})}{(P PCl_{5})}

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6 0
3 years ago
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