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Dahasolnce [82]
3 years ago
12

Chromium is manufactured by heating a mixture of chromium(III) oxide with aluminium powder.

Chemistry
1 answer:
marshall27 [118]3 years ago
8 0
I’m taking a good estimation and gonna say B but I’m torn between that and D
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Explain the concept of electron density
Doss [256]
Electron density is the measure of theprobability of an electron being present at a specific location.

In molecules, regions of electron density are usually found around the atom, and its bonds. In de-localized orconjugated systems, such as phenol,benzene and compounds such as hemoglobin and chlorophyll, the electron density covers an entire region, i.e., in benzene they are found above and below the planar ring. This is sometimes shown diagrammatically as a series of alternating single and double bonds. In the case of phenol and benzene, a circle inside a hexagon shows the de-localized nature of the compound.

5 0
3 years ago
If a bullet travels at 407.0 m/s, what is its speed in miles per hour? Number click to edit mi/h For the same bullet travelling
kaheart [24]

Answer : The speed in miles per hour is 22 mile/hr.

The speed in yard per min is 26617.8 yard/min

Explanation :

The conversion used for meters to miles is:

1m=100cm\times \frac{1in}{2.54cm}\times \frac{1ft}{12in}\times \frac{1mile}{5280ft}

The conversion used for second to hour is:

1s=\frac{1}{60}min\times \frac{1hr}{60min}

The conversion used for meter per second to mile per hour is:

1\frac{m}{s}=\frac{100cm\times \frac{1in}{2.54cm}\times \frac{1ft}{12in}\times \frac{1mile}{5280ft}}{\frac{1}{60}min\times \frac{1hr}{60min}}

As we are given the speed of 407.0 meter per second. Now we have to determine the speed in miles per hour.

1m/s=2.2mile/hr

So, 407.0m/s=\frac{2.2mile/hr}{1m/s}\times 407.0m/s=895.4mile/hr

Therefore, the speed in miles per hour is 22 mile/hr.

The conversion used for meter to yard

1m = 1.09 yard

The conversion used for second to hour is:

1s=\frac{1}{60}min

The conversion used for meter per second to mile per hour is:

1m/s=\frac{1.09yard}{frac{1}{60min}}

1m/s=65.4yard/min

As we are given the speed of 407.0 meter per second. Now we have to determine the speed in yards per min

1m/s=65.4yard/min

So, 407.0m/s=\frac{65.4yard/min}{1m/s}\times 407.0m/s=26617.8yard/min

Therefore, the speed in yard per min is 26617.8 yard/min

7 0
2 years ago
A
DIA [1.3K]
  • V_1=49.8mL
  • T_1=18°C=291K
  • T_2=83°C=356K

Using Charles law

\\ \sf\longmapsto V_1T_2=V_2T_1

\\ \sf\longmapsto V_2=V_1T_2\div T_1

\\ \sf\longmapsto V_2=\dfrac{49.8(356)}{291}

\\ \sf\longmapsto V_2=\dfrac{17728.8}{291}

\\ \sf\longmapsto V_2=60.9mL

5 0
2 years ago
Look at the picture of two different substances above. Which substance is a mixture? A. Y and Z
Feliz [49]

Answer:

option B is correct.

Y is a mixture in the picture.

Explanation:

Different types of substances combine physically and form a mixture.  

Mixture formed by the combination of two or more substances that that combine in same physical state.

For example mixture of copper sulphate and solid chloride in dry form and that will look like white and blue crystal in a mixture.

The picture Z showing dots of same color and is not a mixture, while picture Y shows dots of different colors clearly indicating that it is picture for mixture.

5 0
3 years ago
Read 2 more answers
What term describes the process of lowering the boiling point of a hydrocarbon by exposing it to different environmental treatme
IgorLugansk [536]

Answer:

Cracking.

Explanation:

A chemical reaction can be defined as a reaction in which two or more atoms of a chemical element react to form a chemical compound. An example of a chemical reaction involving hydrocarbons is cracking.

Hydrocarbon can be defined as an organic compound that comprises of hydrogen and carbon only.

In Organic chemistry, cracking refers to the process of lowering the boiling point of a heavy, complex or long-chain hydrocarbon such as kerogens by exposing it to different environmental treatments such as hydrogen enriched catalysts, pressure or high temperatures, in order to produce smaller, lighter and more useful molecules (alkanes and alkenes) such as gasoline, diesel fuel, etc.

8 0
3 years ago
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