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9966 [12]
2 years ago
10

HELP ME PLEASEEE- 8th grade science

Chemistry
1 answer:
icang [17]2 years ago
3 0

Answer:

It's obviously <em><u>LIGHT</u></em><em><u> </u></em><em><u>ENERGY</u></em><em><u> </u></em><u>for</u><u> </u><u>me</u><u> </u><u>cuz</u><u> </u><u>it's</u><u> </u><u>from</u><u> </u><u>the</u><u> </u><u>flashl</u><u>ight</u><u>.</u><u>.</u>

Explanation:

Hope it helps you..

Your welcome in advance..

(ㆁωㆁ)

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pickupchik [31]
For a chemical reaction, the results would be the same with different amounts of barium chloride present if barium chloride is not the limiting reactant of the reaction. The limiting reactant is the substance that is totally consumed when the reaction proceeds to completion. In other words, it dictates the amount of products that will be produced. Otherwise, if barium chloride is the limiting reactant, the amount of barium chloride present would definitely affect the results.  
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3 years ago
Which describes the slope of the graph from 10 s to 30 s?
inna [77]

Answer:

3

Explanation:

Use the rise over run method. plot the necessary points first in the x and y axis

6 0
3 years ago
A solution is 40.00% by volume benzene (C6H6) in carbon tetrachloride at 20°C. The vapor pressure of pure benzene at this temper
finlep [7]

Answer:

The total vapor pressure is 84.29 mmHg

Explanation:

Step 1:  Data given

Solution = 40.00 (v/v) % benzene in CCl4

Temperature = 20.00 °C

The vapor pressure of pure benzene at 20.00 °C = 74.61 mmHg

Density of benzene is 0.87865 g/cm3

The vapor pressure of pure carbon tetrachloride is 91.32 mmHg

We suppose the total volume = 100 mL

Step 2: Calculate volume benzene and CCl4

40 % benzene = 40 mL

60 % mL CCl4 = 60 mL

Step 3: Calculate mass benzene

Mass = density * volume

Mass of benzene = 40.00 mL *  0.87865 g/mL = 35.146 g

Step 4: Calculate moles of benzene

Moles = mass / molar mass

Number of moles of benzene  = 35.146 grams / 78 g/mol  = 0.45059 mol

Step 5: Calculate mass of CCl4

Mass of CCl4 = 60 mL * 1.5940 g/mL = 95.64 g

Step 6: Calculate moles CCl4

Number of moles of CCl4 = 95.64 grams / 154g/mol = 0.62104 mol

Step 7: Calculate total number of moles

Total number of moles = moles benzene + moles CCl4

0.45059 moles + 0.62104 moles = 1.07163 mol

Step 8: Calculate mole fraction benzene and CCl4

Mole fraction = moles benzene / total moles

Mole fraction of benzene = 0.45059 / 1.07163 = 0.4205

Mole fraction of CCl4 = 0.62104 / 1.07163 = 0.5795

Step 9: Calculate partial pressure

Partial pressure of benzene = 0.4205 * 74.61 = 31.37 mmHg

Partial pressure of CCl4      = 0.5795 * 91.32 = 52.92 mmHg

Total vapor pressure = 31.37 + 52.92 = 84.29 mmHg

The total vapor pressure is 84.29 mmHg

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2 years ago
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A sodium atom has a mass number of 23. Its atomic number is 11. How many electrons does a neutral sodium atom have?
NemiM [27]

Answer:

it contains 11 electrons

Explanation:

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