You will get iron sulfate and hydrogen sulfide gas (a.k.a. rotten egg gas).
FeS + H2SO4 = FeSO4 + H2S(g)
Change in Free Energy: ΔG(20C) = -66.6kJ (negative, so the reaction runs)
Change in Enthalpy: ΔH(20C) = -37.3kJ (negative, so the reaction is exothermic)
Unbalanced chemical reaction: PbO₂ + I₂ → Pb²⁺ +IO₃⁻<span>.
First </span><span>determine oxidation numbers of elements:
1) lead on the left side of reaction has oxidation number +4 (x + 2</span>·(-2) = 0) and on the right side +2, so lead is reduced.
2) iodine has neutal charge (0) on left and oxidation number +5 on the right side of chemical reaction (x + 3 · (-2) = -1), so iodine is oxidized.
3) oxygen has oxidation number -2 on both side of chemical reaction.
Second, write balanced half reactions, because this reaction is acidic solution, add hydrogen ions on one side and water on another side of half reaction; balance atoms and electrons on both half reactions:
Half reaction 1: PbO₂ + 4H⁺ + 2e⁻ → Pb²⁺ + 2H₂O /×5
5PbO₂ + 20H⁺ + 10e⁻ → 5Pb²⁺ + 10H₂O.
Half reaction 2: I₂ + 6H₂O → 2IO₃⁻ + 12H⁺ + 10e⁻.
Sum both half reactions and short same ions:
5PbO₂ + 20H⁺ + I₂ + 6H₂O → 5Pb²⁺ + 10H₂O + 2IO₃⁻ + 12H⁺.
Abbreviate reaction: 5PbO₂ + 8H⁺ + I₂ → 5Pb²⁺ + 4H₂O + 2IO₃⁻..
Your conclusions summarize how your results support or contradict your original hypothesis: Summarize your science fair project results in a few sentences and use this summary to support your conclusion.
Answer:
Explanation:
Balancing Carbon atoms on the right side,
Balancing Hydrogen atoms on the right side,
Balancing Oxygen atoms on the left side,
The reactants are on the left side of the reaction:
Propane and oxygen are the reactants.
The products are on the right side of the reaction:
Carbon dioxide and water are the products.
forgive me if im incorrect or leaving things out
