Answer:
6 moles of CuCl₂ will produced 4 moles of AlCl₃ .
Explanation:
Given data:
Moles of CuCl₂ = 6 mole
Moles of AlCl₃ produced = ?
Solution:
3CuCl₂ + 2Al → 2AlCl₃ + 3Cu
Now we will compare the moles of CuCl₂ with AlCl₃ .
CuCl₂ : AlCl₃
3 : 2
6 : 2/3 ×6 = 4 mol
So, 6 moles of CuCl₂ will produced 4 moles of AlCl₃ .
Explanation:
The question pretty much requires us to find the amount of moles of each compounds based on the number of moles of O given.
H2SO4
1 mol of H2SO4 contains 4 mol of O
x mol of H2SO4 would contain 3.10 mol of O
x = 3.10 * 1 / 4 = 0.775 mol of H2SO4
C2H4O2
1 mol of C2H4O2 contains 2 mol of O
x mol of C2H4O2 would contain 3.10 mol of O
x = 3.10 * 1 / 2 = 1.55 mol of C2H4O2
NaOH
1 mol of NaOH contains 1 mol of O
x mol of NaOH would contain 3.10 mol of O
x = 3.10 * 1 / 1 = 3.10 mol of NaOH
