I believe the correct answer is 11 g
Answer:
See explanation
Explanation:
The question is incomplete because the images of the models are absent. However, i will try to give you a general description of what the correct answer should be.
Beryllium is a member of group 2 in the periodic table. Beryllium has an atomic number of 4. This implies that it has four protons in its nucleus and four electrons in its shells. In a neutral atom, the number of electrons on the shells is equal to the number of protons in the nucleus.
The electronic configuration of Beryllium is 1s2 2s2. This implies that it should have two shells each containing only two electrons each.
Since we are using white foam balls for protons and black foam balls for neutrons, the clear plastic will contain four white foam balls and five black foam balls since the mass number of beryllium is 9 and number of neutrons = mass number - number of protons.
Four blue foam balls hanging from strings will represent the electrons around the nucleus.
Any model that corresponds to the description above is the correct answer.
Special properties of water are its high heat capacity and heat of vaporization, its ability to dissolve polar molecules, its cohesive and adhesive properties, and its dissociation into ions that leads to generating pH. Understanding these characteristics of water helps to elucidate its importance in maintaining life.
Answer:

<em><u>Step by step explanation</u></em><em><u>:</u></em>
<em>Given:</em>
Mass of given sample (m) = 2.50 g
Initial temperature (T1) = 25°C
Final temperature (T2) = 20°C
Heat Energy Q = 12 cal
<em>T</em><em>o </em><em>find:</em>
<em>
</em>
<em>Solution</em><em>:</em>
We know that,
<em>Specific</em><em> </em><em>heat</em> <em>of </em><em>any </em><em>substance </em><em>is </em><em>directly</em><em> </em><em>proportional</em><em> </em><em>to </em><em>the </em><em>mass </em><em>and </em><em>change </em><em>in </em><em>temperature.</em>
Represented by equation,

Where,
<em>Q = Heat Energy</em>
<em>m = mass of given sampl</em><em>e</em>
<em>c = specific heat</em>
<em>∆T = change in </em><em>temperature</em>
Substituting corresponding values,
<em>
</em>
We also know that,

multiplying above answer by 4.184,

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