The inverted cone, hope it helps .
Answer:
Is insufficient to overcome intermolecular forces.
Explanation:
Hope this helps
Please let me know if I'm wrong
The concentration of iron used in the titration : 0.009 M
<h3>Further explanation</h3>
Given
Reaction
Cr₂O₇²⁻ + 6Fe²⁺ + 14H⁺ ⇒ 2Cr³⁺ + 6Fe³⁺ + 7H₂O
0.0093 mol/L potassium dichromate
200 cm³ of dilute acid, 25cm³ was used in the titration.
Required
the concentration of iron
Solution
Titration formula
C₁V₁n₁=C₂V₂n₂⇒ From equation : n₁=6n₂(1=Cr₂O₇, 2=Fe)
titration average : 33+32.05+32.15+32.1 / 4 = 32.325 cm³(ml)
25 cm³ of iron solution used in titration :

Dilution(25 ml from 200 ml iron solution)

Answer:
144.08 g of H₂O
Explanation:
The balance chemical equation for the synthesis of water is as follow;
2 H₂ + O₂ → 2 H₂O
Step 1: <u>Find out moles of H₂O produced as;</u>
According to balance chemical equation,
1 mole of O₂ produced = 2 moles of H₂O
So,
4 moles of O₂ will produce = X moles of H₂O
Solving for X,
X = 4 mol × 2 mol / 1 mol
X = 8 moles of H₂O
Step 2: <u>Calculate Mass of H₂O as;</u>
Mass = Moles × M.Mass
Mass = 8 mol × 18.01 g/mol
Mass = 144.08 g of H₂O
The question is incomplete, here is the complete question:
A chemist prepares a solution of iron (III) bromide
by measuring out 2.78 g of iron (III) bromide into a 50. mL volumetric flask and filling the flask to the mark with water.
Calculate the concentration in mmol/L of the chemists iron (III) bromide solution. Be sure your answer has the correct number of significant digits.
<u>Answer:</u> The concentration of iron(III) bromide solution is 0.19 M
<u>Explanation:</u>
To calculate the molarity of solution, we use the equation:

We are given:
Given mass of iron(III) bromide = 2.78 g
Molar mass of iron(III) bromide = 298.6 g/mol
Volume of solution = 50. mL
Putting values in above equation, we get:

Hence, the concentration of iron(III) bromide solution is 0.19 M