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makkiz [27]
2 years ago
14

HELPPPPPPPPPPPPPPP PLZZZZZZZZZZZZZz

Mathematics
1 answer:
iragen [17]2 years ago
6 0

Answer:

basically a calculator

Step-by-step explanation:

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Identify the center and the radius of the circle given by the equation (x – 4)2 + (y+13)2 = 289.
VMariaS [17]

Answer:

Center: (4,-13)

Radius: 17

Step-by-step explanation:

I guess you do not need an explanation, so I gave you only an answer.

7 0
2 years ago
To win at LOTTO in a certain state, one must correctly select 6 numbers from a collection of 52 numbers (1 through 52). The orde
miv72 [106K]

Answer:

The answer is 20,358,520

Step-by-step explanation:

Selecting 6 numbers from a collection of 52 numbers regardless of order involves a combination.

Note: if regards was taken into order of selection, this would be a permutation.

Hence, the different 6 number selections out of 52 is

52C6 = 52! / [6!*(52-6)!]

= 52!/(6!*46!)

= 20,358,520

7 0
3 years ago
Tentukan mean, median, dan modus dari 7,4,5,6,7,4,5,7,8,9, dan 6
Anvisha [2.4K]

Answer:

<h3>Median = 6</h3><h3>Mean = 6,1</h3><h3>Modus = 7</h3>

Step-by-step explanation:

Median (Nila tengah setelah data diurutkan)

= 4, 4, 5, 5, 6, 6, 7, 7, 7, 8, 9

= 6

Mean

= jumlah data / banyak data

= 4+4+5+5+6+6+7+7+7+8+9/11

= 68/11

= 6,1

Modus

= data yang paling banyak muncul

= 7 (muncul sebanyak 3 kali)

3 0
3 years ago
g A researcher wants to construct a 95% confidence interval for the proportion of children aged 8-10 living in Atlanta who own a
Helga [31]

Answer:

The sample size needed is 2401.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error of the interval is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Estimate the sample size needed if no estimate of p is available so that the confidence interval will have a margin of error of 0.02.

We have to find n, for which M = 0.02.

There is no estimate of p available, so we use \pi = 0.5

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.02 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.02\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.02}

(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.02})^{2}

n = 2401

The sample size needed is 2401.

7 0
3 years ago
Read 2 more answers
(6/11) to the power 2 answer pls
Lana71 [14]

Step-by-step explanation:

in fraction it comes 36/121

and in decimal.it comes 0.3

5 0
3 years ago
Read 2 more answers
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