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Lerok [7]
3 years ago
15

I WILL GIVE BRAINLIEST!!!!!

Physics
2 answers:
Lilit [14]3 years ago
7 0
The first one 10 ft-lbs I think
kumpel [21]3 years ago
6 0

Answer:

It's 10 ft-lbs

Explanation:

In that case work done is not associated with time.

We will consider only Force aplied and the distance covered in the direction of force.

Therefore, Work done = Force × distance

= 2 lbs × 5 ft

= 10 ft-lbs

But in most cases answers are written in SI units.

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C. Destructive interference

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3 years ago
Read 2 more answers
It is 4.0 km from your home to the physics lab. As part of your physical fitness program, you could run that distance at 10 km/h
Musya8 [376]

Answer:

Explanation:

To solve this problem we have to take into account that the energy consumed per second is the power. Hence, by multipling the power and the time spent to arrive to the lab we obtain the total energy consumed.

But first we have to calculate the time

t_{1}=\frac{x}{v_{1}}=\frac{4km}{10\frac{km}{h}}=0.4h=0.4(3600s)=1440s\\t_{2}=\frac{x}{v_{2}}=\frac{4km}{3\frac{km}{h}}=1.3h=1.3(3600s)=4800s\\

Now we use E=W*t for both times

E_{1}=t_{1}W_{1}=(1440s)(700W)=1008000J\\E_{2}=t_{2}W_{2}=(4800s)(290W)=1392000J\\

A. Hence, by running the energy consumed is lower.

B.

E1=1008000J

E2=1392000J

C. Because the more intense exercise is made in a lower time in comparison with the less intense exercise, and higher the time, more energy is consumed.

5 0
3 years ago
How do I know what kinematic equations to use when solving a question?
olganol [36]

Explanation:

There are 5 kinematic equations, and 5 variables.

Each question will give you 3 variables and ask you to solve for a fourth.

To determine which equation to use, look at which variable is <em>not</em> included in the problem.

For example, if the question does not include time, then you need to use a kinematic equation that does not have t in it.  That would be:

v² = v₀² + 2aΔx

Or, if the question does not include the final velocity, then you need a kinematic equation that does not have v in it.  That would be:

Δx = v₀ t + ½ at²

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pychu [463]
Acceleration, a =  (v - u) / t

Initial Velocity, u = 30 m/s
Final Velocity, v  =  23 m/s
time                 t  =  2.00 seconds

a = (23 - 30) / 2
a = -7 / 2 = -3.5 m/s2

So the acceleration  is negative, which means it is a deceleration of 3.5 m/s2.
8 0
3 years ago
Two 2.0-mm diameter beads, C and D, are 12mm mm apart, measured between their centers. Bead C has mass 1.0 g and charge 2.5nC nC
Artist 52 [7]

Answer:

d

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7 0
3 years ago
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