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Leno4ka [110]
3 years ago
9

What are the two factors that affect the period of a pendulum?

Physics
1 answer:
klemol [59]3 years ago
3 0
The two factors that affect the period of a pendulum are the length of the string and the distance in which the pendulum falls.

Hope this helps! I would greatly appreciate a brainliest! :)
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Suppose that the weight (in pounds) of an airplane is a linear function of the amount of fuel (in gallons) in its tank. When car
Inessa [10]

Answer:

W=2219pounds

Explanation:

If the weight  is a linear function of the amount of fuel, the following correlation is fulfilled :

\frac{2153pounds-1999pounds}{46gallons-18gallons} = \frac{W-1999pounds}{58gallons-18galons}

we solve the equation:

W=2219pounds

6 0
3 years ago
Predict the magnitude of the gravitational force....
Galina-37 [17]

Answer:

a=650.549

b=246.4819

c=38.5261

Explanation:

7 0
2 years ago
You drop a 0.375 kg ball from a height of 1.37 m. It hits the ground and bounces up again to a height of 0.67 m. How much energy
Radda [10]

2.57 joule energy lose in the bounce .

<u>Explanation</u>:

when ball is the height of 1.37 m from the ground  it has some gravitational potential energy with respect to hits the ground  

Formula for gravitational potential energy given by  

Potential Energy = mgh

Where ,

m = mass  

g = acceleration due to gravity  

h = height

Potential energy when ball hits the ground

m= 0.375 kg

h = 1.37 m

g = 9.8 m/s²

Potential Energy = 0.375\times9.8\times1.37

Potential Energy = 5.03 joule

Potential energy when ball bounces up again

h= 0.67 m

Potential Energy = 0.375\times0.67\times9.8

Potential Energy = 2.46 joule

Energy loss = 5.03 - 2.46 = 2.57 joule

2.57 joule energy lose in the bounce

6 0
3 years ago
A 790kg car moving at 7 m/s takes a turn around a circle with a radius of 20 m. Determined the net force (in Newton’s) acting up
prisoha [69]

1935.5 N is the "net force" acting on a car.

<u>Explanation</u>:

Given that,  

Mass of the car is 790 kg.

Velocity of the car is 7 m/s. (v)

It turned around with 20 m. (r)  

We know that, Net force = m × a

\text { Here, acceleration of the car is radial acceleration } a_{\mathrm{rad}}=\frac{v^{2}}{r}

\mathrm{a}_{\mathrm{rad}}=\frac{7^{2}}{20}

\mathrm{a}_{\mathrm{rad}}=\frac{49}{20}

a_{\text {rad }}=2.45 \mathrm{m} / \mathrm{s}^{2}

Now, Net force = m × a

Net force = 790 × 2.45

Net force = 1935.5 N

4 0
3 years ago
Contact force that acts to resist sliding between two touching surfaces
Black_prince [1.1K]
I think that the answer is friction 
3 0
3 years ago
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