1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
blsea [12.9K]
3 years ago
12

What type of pollution is pictured here?

Chemistry
1 answer:
Svetlanka [38]3 years ago
8 0

Answer:this air polluction here.

Explanation:

air and soil polluction

You might be interested in
Before we can analyze the alum crystal it is
dusya [7]

Answer: TRUE

Explanation:

3 0
3 years ago
Which metal is more active than NI and less active than Zn?
Mademuasel [1]

Answer : The correct option is, (2) Cr (Chromium)

Explanation :

The reactivity series of metal are arranged of the reactivity from the highest to the lowest. Reactivity series is used to determine the products of the single displacement reactions. In the single displacement reaction, the most reactive metal displaces the least reactive metal.

From the given reactivity series we conclude that there are two metal (Mg and Cr) are more reactive metal than the Ni and there are two metal (Pb and Cr) are less reactive metal than the Zn. So, the Cr (Chromium) is the metal which is more active than Ni and less active than Zn.

Hence, the correct option is, (2) Cr

7 0
4 years ago
Read 2 more answers
One set of environmental factors lists ONLY biotic factors. That is
Dmitry_Shevchenko [17]
I hope this helps you

5 0
3 years ago
Read 2 more answers
Calculate the pH for the following weak acid. A solution of HCOOH has 0.12M HCOOH at equilibrium. The Ka for HCOOH is 1.8×10−4.
Shtirlitz [24]

Answer:

the pH of HCOOH solution is 2.33

Explanation:

The ionization equation for the given acid is written as:

HCOOH\leftrightarrow H^++HCOO^-

Let's say the initial concentration of the acid is c and the change in concentration x.

Then, equilibrium concentration of acid = (c-x)

and the equilibrium concentration for each of the product would be x

Equilibrium expression for the above equation would be:

\Ka= \frac{[H^+][HCOO^-]}{[HCOOH]}

1.8*10^-^4=\frac{x^2}{c-x}

From given info, equilibrium concentration of the acid is 0.12

So, (c-x) = 0.12

hence,

1.8*10^-^4=\frac{x^2}{0.12}

Let's solve this for x. Multiply both sides by 0.12

2.16*10^-^5=x^2

taking square root to both sides:

x=0.00465

Now, we have got the concentration of [H^+] .

[H^+] = 0.00465 M

We know that, pH=-log[H^+]

pH = -log(0.00465)

pH = 2.33

Hence, the pH of HCOOH solution is 2.33.

7 0
3 years ago
Read 2 more answers
Commercially available concentrated sulfuric acid is 17.2M . Calculate the volume of concentrated sulfuric acid required to prep
Dimas [21]

Answer:

0.727 l.

Explanation:

For the new dilute Sulphuric acid,

Number of moles = molar concentration × volume

= 2.5 × 5

= 12.5 mol

Volume of concentrated solution = 12.5/17.2

= 0.727 l of 17.2 M of sulphuric acid to be diluted.

5 0
3 years ago
Other questions:
  • If an electron fell to a lower orbit or energy level, energy would be
    14·2 answers
  • What is the chemical formula of fomic acid?
    11·1 answer
  • How does a lithium cation compare to a lithium atom?
    14·1 answer
  • As air molecules move over and under the wings of an airplane, the pressure
    5·2 answers
  • Imagine that you are in the laboratory and find broken glass on your
    5·2 answers
  • You have a 275 mg sample of a compound that contains aluminum and a group 7A element (F, Cl, Br, I or At). This compound reacts
    8·1 answer
  • A cart weighing 13kg is pushed by a vendor. If the cart accelerates at 3.5 m/s2
    9·1 answer
  • At room temperature (20°C} and pressure, the density of air is 1.189 g/L. An object will float in air if its density is less tha
    10·1 answer
  • Determine the hydronium ion concentration Big Points
    15·1 answer
  • How do I learn a subject easier
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!