Can someone help me with this please thank you
2 answers:
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Answer:
91.92% probability that the mean annual precipitation during 49 randomly picked years will be less than 106.8 inches
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal probability distribution:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central limit theorem:
The Central Limit Theorem estabilishes that, for a random variable X, with mean and standard deviation
, the sample means with size n of at least 30 can be approximated to a normal distribution with mean
and standard deviation
In this problem, we have that:
What is the probability that the mean annual precipitation during 49 randomly picked years will be less than 106.8 inches
This is the pvalue of Z when X = 106.8. So
By the Central Limit Theorem
has a pvalue of 0.9192
0.9192 = 91.92% probability that the mean annual precipitation during 49 randomly picked years will be less than 106.8 inches
⇒I will first isolate y together with its coefficient k by placing to the right hand side...
⇒Now to leave y independent we have to divide ky by the coefficient of y which in this case is k.
⇒Meaning k will divide all the terms in the equation.
⇒Attached is the answer.
Answer: (A)
Explanation: For there to be a solution at any one point, both inequalities must share a common point. This point will then satisfy both inequations, becoming a solution to both inequality.
Let's pick (A).
For there to be at least one solution, the first inequality must have a solution of
. Since the left side has clearly no points common to both graphs. Hence, no solution can exist that will satisfy both.
All of the other graphs have at least one point in common.
(B) has
(C) has
(D) has
Explanation: For there to be a solution at any one point, both inequalities must share a common point. This point will then satisfy both inequations, becoming a solution to both inequality.
Let's pick (A).
For there to be at least one solution, the first inequality must have a solution of
All of the other graphs have at least one point in common.
(B) has
(C) has
(D) has