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Pie
3 years ago
13

Why do we use mercury in thermometer​

Physics
1 answer:
viktelen [127]3 years ago
4 0

Answer:

Mercury is the only one in liquid state at room temperature. It's used in thermometers because it has high coefficient of expansion.  It also has a high boiling point which makes it very suitable to measure higher temperatures. Also, it has a shiny appearance and doesn't stick to the glass surface of glass.

Explanation:

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A 50-cm^3 block of wood is floating partially submerged in water, and a 50-cm^3 block of iron is totally submerged in water. Whi
sergeinik [125]

Answer:

B) The iron

Explanation:

Both blocks have the same volume. Since the wood is partially submerged, it displaces a smaller volume of fluid than the iron, that is completely submerged. The buoyant force is proportional to the volume of the displaced fluid. Therefore, the buoyant force on iron is greater.

6 0
4 years ago
A.) A bullet accelerates at 8000 m/s2
lukranit [14]

Answer:

0.02 s

160 m/s

Explanation:

Given:

Δx = 1.6 m

v₀ = 0 m/s

a = 8000 m/s²

A) Find t.

Δx = v₀ t + ½ at²

1.6 m = (0 m/s) t + ½ (8000 m/s²) t²

t = 0.02 s

B) Find v.

v² = v₀² + 2aΔx

v² = (0 m/s)² + 2 (8000 m/s²) (1.6 m)

v = 160 m/s

6 0
3 years ago
Mercury has an average disease to the sun of 0.39 AU. In two or more complete sentences, explain how to calculate the orbital pe
alukav5142 [94]

Answer: 88 Earth days

Explanation:

According to the Kepler Third  Law of Planetary motion <em>“The square of the orbital period of a planet is proportional to the cube of the semi-major axis (size) of its orbit”. </em>

<em />

In other words, this law states a relation between the orbital period T of a body (moon, planet, satellite) orbiting a greater body in space with the size a of its orbit:

T^{2}=a^{3} (1)

If we assume the orbit is circular and apply Newton's law of motion and the Universal Law of Gravity we have:

T^{2}=\frac{4\pi^{2}}{GM}a^{3} (2)

Where M is the mass of the massive object and G is the universal gravitation constant. If we assume M constant and larger enough to consider G  really small, we can write a general form of this law:

MT^{2}=a^{3} (3)

Where T is in units of Earth years,  a is in AU (<u>1 Astronomical Unit is the average distane between the Earth and the Sun)</u> and  M is the mass of the central object  in units of the mass of the Sun.

This means when we are making calculations with planets in our solar system  M=1.

Hnece, in the case of Mercury:

(1)T^{2}=(0.39 AU)^{3} (4)

Isolating T:

T=\sqrt{(0.39 AU)^{3}} (5)

T=0.243 Earth-years \frac{365 days}{1 Earth-year}=88.6 days \approx 88 days (6)

This means the period of Mercury is 88 days.

7 0
3 years ago
Ok plz help this is my entrance exam question for physics in grade 9 (yes i am moving to a new school again)
vagabundo [1.1K]

Answer:

300 W

Explanation:

We know that

P = W/t

P = mgh/t

P = 40 × 10 × 3/4

P = 10 × 10 × 3

P = 300 W

4 0
3 years ago
I'm thinking A?
Luba_88 [7]

Hey girl

the answer is A

your correct the atmosphere provides warmth


hope this helps

XD


5 0
3 years ago
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