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3 years ago

Why do the snakes only get one unit of energy?

Physics

1 answer:

mojhsa [17]3 years ago

7 0

Answer: Snakes are reptiles

Explanation: All reptiles are ectothermic (they obtain body heat from their environment).

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Write 3 rules that describe the possible behaviors that occur when objects with different charges are brought close together

REY [17]

Explanation:

1. attract

2.repel

3. no effect

8 0

3 years ago

A bathtub has 62.7 kg of water at 31.0

Bogdan [553]

m = mass of water in bathtub = 62.7 kg

$T_{ti}$ = initial temperature of water in tub = 31 c

M = mass of water added = ?

$T_{ai}$ = initial temperature of water added = 76 c

T = final equilibrium temperature of the system = 40.3 c

c = specific heat of water = 4186

Using conservation of heat

Heat gained by water in tub = Heat lost by water added

m c (T - $T_{ti}$ ) = M c ( $T_{ai}$ - T)

m (T - $T_{ti}$ ) = M ( $T_{ai}$ - T)

(62.7) (40.3 - 31) = M (76 - 40.3)

M = 16.3 kg

5 0

3 years ago

Máy điện không đồng bộ là loại máy điện xoay chiều, làm việc theo nguyên lý

Sidana [21]

https://vt.tiktok.com/ZSejgvyRC/Waaazuupp!!

6 0

3 years ago

A +3.4 x 10-6 C test charge experiences forces from two other nearby charges: a 3 N force due east and a 15 N force due west. Wh

Alecsey [184]

Answer:

3.53×10⁶ N/c due west

Explanation:

From the question

E = F'/q........................ Equation 1

Where E = Electric Field, F = Net Force, q = Charge.

But,

F' = F₂-F₁...................... Equation 2

Substitute equation 2 into equation 1

E = (F₂-F₁)/q................ Equation 3

Given: F₁ = 3 N due east, F₂ = 15 N due west, q = 3.4×10⁻⁶ C

Substitute these values into equation 1

E = (15-3)/(3.4×10⁻⁶)

E = 12/(3.4×10⁻⁶)

E = 3.53×10⁶ N/c due west

4 0

3 years ago

A square wave has amplitude 0 V for the low voltage and 4 V for the high voltage. Calculate the average voltage by integrating o

Margarita [4]

Answer:

V_{average} = $\frac{1}{2} V_o$ , V_{average} = 2 V

Explanation:

he average or effective voltage of a wave is the value of the wave in a period

V_average = ∫ V dt

in this case the given volage is a square wave that can be described by the function

V (t) = $\left \{ {{V=V_o \ \ \ t< \tau /2} \atop {V=0 \ \ \ \ t> \tau /2 } } \right.$

to substitute in the equation let us separate the into two pairs

V_average = $\int\limits^{1/2}_0 {V_o} \, dt + \int\limits^1_{1/2} {0} \, dt$

V_average = $V_o \ \int\limits^{1/2}_0 {} \, dt$

V_{average} = $\frac{1}{2} V_o$

we evaluate V₀ = 4 V

V_{average} = 4 / 2)

V_{average} = 2 V

6 0

3 years ago