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rodikova [14]
3 years ago
15

Help with this question please :>

Physics
2 answers:
defon3 years ago
5 0

Answer: It's c

Explanation: C

zheka24 [161]3 years ago
3 0

Answer: A if thats not right its C

Explanation:

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How is sound wave produced?​
kramer

Answer:

Sound is produced when an object vibrates, creating a pressure wave.

Explanation:

This pressure wave causes particles in the surrounding medium (air, water, or solid) to have vibrational motion. ... The human ear detects sound waves when vibrating air particles vibrate small parts within the ear.

3 0
3 years ago
Read 2 more answers
Hi, pls help with this question. Thank you.
topjm [15]

Answer:

i: Gamma Rays

ii: Infrared

Explanation:

It just is:)

5 0
3 years ago
Two loudspeakers are about 10 mm apart in the front of a large classroom. If either speaker plays a pure tone at a single freque
Yuliya22 [10]

Answer:

I hear points of low volume sound and points of high volume of sound.

Explanation:

This is because, since the two sources of sound have the same frequency and are separated by a distance, d = 10 mm, there would be successive points of constructive and destructive interference.

Since their frequencies are similar, we should have beats of high and low frequency.

So, at points of low frequency, the amplitude of the wave is smallest and there is destructive interference. The frequency at this point is the difference between the frequencies from both speakers. Since the frequency from both speakers is 400 Hz, we have, f - f' = 400 Hz - 400 Hz = 0 Hz. So, the volume of the sound is low(zero) at these points.

Also, at points of high frequency, the amplitude of the wave is highest and there is constructive interference. The frequency at this point is the sum between the frequencies from both speakers. Since the frequency from both speakers is 400 Hz, we have, (f + f') = 400 Hz + 400 Hz = 800 Hz. So, the volume of the sound is high at these points.

So, as you wander around the room, I should hear points of high and low sound across the room.

6 0
3 years ago
Which of the following is a transformer used for?
mamaluj [8]

A transformer is used to increase or decrease a voltage.  BUT ... it has to be an AC voltage, or the transformer doesn't work.

5 0
3 years ago
Read 2 more answers
A miniature quadcopter is located at x = -2.25 m and y, - 5.70 matt - 0 and moves with an average velocity having components Vv,
kupik [55]

Recall that average velocity is equal to change in position over a given time interval,

\vec v_{\rm ave} = \dfrac{\Delta \vec r}{\Delta t}

so that the <em>x</em>-component of \vec v_{\rm ave} is

\dfrac{x_2 - (-2.25\,\mathrm m)}{1.60\,\mathrm s} = 2.70\dfrac{\rm m}{\rm s}

and its <em>y</em>-component is

\dfrac{y_2 - 5.70\,\mathrm m}{1.60\,\mathrm s} = -2.50\dfrac{\rm m}{\rm s}

Solve for x_2 and y_2, which are the <em>x</em>- and <em>y</em>-components of the copter's position vector after <em>t</em> = 1.60 s.

x_2 = -2.25\,\mathrm m + \left(2.70\dfrac{\rm m}{\rm s}\right)(1.60\,\mathrm s) \implies \boxed{x_2 = 2.07\,\mathrm m}

y_2 = 5.70\,\mathrm m + \left(-2.50\dfrac{\rm m}{\rm s}\right)(1.60\,\mathrm s) \implies \boxed{y_2 = 1.70\,\mathrm m}

Note that I'm reading the given details as

x_1 = -2.25\,\mathrm m \\\\ y_1 = -5.70\,\mathrm m \\\\ v_x = 2.70\dfrac{\rm m}{\rm s}\\\\ v_y=-2.50\dfrac{\rm m}{\rm s}

so if any of these are incorrect, you should make the appropriate adjustments to the work above.

8 0
3 years ago
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