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Nataly_w [17]
3 years ago
7

To test the effectiveness of a gunpowder mixture, 1 gram was exploded under controlled STP conditions, and the reaction chamber

was found to expand to 310 cm3. What volume would these gases occupy at the temperature produced by an uncontrolled explosion (2,200°C) and 2.1 atmospheres of pressure? 5,900 cm3 1,300 cm3 7.7 x 104 cm3 1,000 cm3
Chemistry
2 answers:
Gnom [1K]3 years ago
8 0

Answer:

1300 cm 3

Explanation:

Phoenix [80]3 years ago
3 0

Answer:

The volume of the gas at given temperature is 1300 cm^3

Explanation:

P_1 = initial pressure of gas = 1 atm

T_1 = initial temperature of gas = 0^oC=273.15 K

V_1 = initial volume of gas = 310 cm^3 = 310 mL = 0.310 L

(1 cm^3= 1mL , 1 mL = 0.001 L)

P_1V_1=nRT_1..[1]

P_2 = final pressure of gas = 2.1 atm

T_2 = final temperature of gas = 2,200^oC=273+2200 K=2473.15 K

V_2 = final volume of gas = ?

P_2V_2=nRT_2..[2]

By dividing [1] and [2] we get combined gas equation :,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

V_2=\frac{P_1V_1\times T_2}{T_1\times P_2}

Now put all the given values in the above equation, we get:

V_2=\frac{1 atm\times 0.310 L\times 2473.15 K}{273.15 K\times 2.1 atm}

V_2=1.3 L=1300 mL= 1300 cm^3

The volume of the gas at given temperature is 1300 cm^3

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What Is the name of the force that holds together the sub Tomic particles of the nuclear?
Alborosie

the nucleus of an atom is held together by the strong force, while the electrons are held in the atom by the electric force.

6 0
3 years ago
Use the atomic mass of indium to calculate the relative abundance of indium-113.
ASHA 777 [7]

The relative abundance of indium-113 is 4%.

The isotopes are species of the same element having the same atomic number but a different mass number.

The elements occurring in nature exist as multiple isotopes.

When we take into account the existence of these isotopes and their relative abundance (percent), the average atomic mass of that element can be computed, which is given by the following formula,

Average atomic Mass= (%age of isotope 1) x (Mass of isotope 1) + (%age of isotope 2) x (Mass of isotope 2)/100

Indium exists in the form of Indium-113 and Indium-115.

The mass of Indium-113 is 112.90 u.

The mass of Indium-115 is 114.90 u.

The average atomic mass of Indium is 114.82 u.

Let the %age of isotope 1(Indium-113) be X.

Then, the %age of isotope 2(Indium-115) would be 100-X.

Applying the values in the formula,

Average atomic mass = 112.90X+114.90(100-X)

114.82 = 112.90X+114.90(100-X)

On solving the above equation, the value of X comes out to be 4%.

Thus, the relative abundance/%age abundance of Indium-113 is 4%.

To know more about "Average Atomic Mass", refer to the following link:

brainly.com/question/13753702?referrer=searchResults

#SPJ4

7 0
1 year ago
An organic compound is 61.5% C, 2.56% H and 35.9% N by mass. 2.00 grams of this gas is entered into a 300.0 mL flask and heated
pashok25 [27]

Answer:

C₄H₂N₂

Explanation:

First we<u> calculate the moles of the gas</u>, using PV=nRT:

P = 2670 torr ⇒ 2670/760 = 3.51 atm

V = 300 mL ⇒ 300/1000 = 0.3 L

T = 228 °C ⇒ 228 + 273.16 = 501.16 K

  • 3.51 atm * 0.3 L = n * 0.082atm·L·mol⁻¹·K⁻¹ * 501.16 K
  • n = 0.0256 mol

Now we<u> calculate the molar mass of the compound</u>:

  • 2.00 g / 0.0256 mol = 78 g/mol

Finally we use the percentages given to<em> </em><u>calculate the empirical formula</u>:

  • C ⇒ 78 g/mol * 61.5/100 ÷ 12g/mol = 4
  • H ⇒ 78 g/mol * 2.56/100 ÷ 1g/mol = 2
  • N ⇒ 78 g/mol * 35.9/100 ÷ 14g/mol = 2

So the empirical formula is C₄H₂N₂

6 0
3 years ago
Calculate the ratio of naf to hf required to create a buffer with ph = 4.05.
NARA [144]
PH is the test of acidity or basicity of a solution. it follows the formula: 
pH = pKa + log [salt] / [acid] where NaF is the salt and HF is the acid in this case. 

By literature, Ka of HF is 3.5*10^-4 
<span>pKa= -log(Ka)=</span><span> 3.46 </span>

<span>pH = pKa + log [NaF / [HF] </span>

4.05 = 3.46 + log [NaF / [HF] 

log [NaF / [HF]<span> = 0.59
</span>
[NaF / [HF] = 3.89
4 0
3 years ago
Read 2 more answers
PLEASE HELP QUICK!
Mila [183]

Answer:A

Explanation:

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6 0
2 years ago
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