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Nataly_w [17]
3 years ago
7

To test the effectiveness of a gunpowder mixture, 1 gram was exploded under controlled STP conditions, and the reaction chamber

was found to expand to 310 cm3. What volume would these gases occupy at the temperature produced by an uncontrolled explosion (2,200°C) and 2.1 atmospheres of pressure? 5,900 cm3 1,300 cm3 7.7 x 104 cm3 1,000 cm3
Chemistry
2 answers:
Gnom [1K]3 years ago
8 0

Answer:

1300 cm 3

Explanation:

Phoenix [80]3 years ago
3 0

Answer:

The volume of the gas at given temperature is 1300 cm^3

Explanation:

P_1 = initial pressure of gas = 1 atm

T_1 = initial temperature of gas = 0^oC=273.15 K

V_1 = initial volume of gas = 310 cm^3 = 310 mL = 0.310 L

(1 cm^3= 1mL , 1 mL = 0.001 L)

P_1V_1=nRT_1..[1]

P_2 = final pressure of gas = 2.1 atm

T_2 = final temperature of gas = 2,200^oC=273+2200 K=2473.15 K

V_2 = final volume of gas = ?

P_2V_2=nRT_2..[2]

By dividing [1] and [2] we get combined gas equation :,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

V_2=\frac{P_1V_1\times T_2}{T_1\times P_2}

Now put all the given values in the above equation, we get:

V_2=\frac{1 atm\times 0.310 L\times 2473.15 K}{273.15 K\times 2.1 atm}

V_2=1.3 L=1300 mL= 1300 cm^3

The volume of the gas at given temperature is 1300 cm^3

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