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3 years ago

7

To test the effectiveness of a gunpowder mixture, 1 gram was exploded under controlled STP conditions, and the reaction chamber

was found to expand to 310 cm3. What volume would these gases occupy at the temperature produced by an uncontrolled explosion (2,200°C) and 2.1 atmospheres of pressure? 5,900 cm3 1,300 cm3 7.7 x 104 cm3 1,000 cm3

2 answers:

Gnom [1K]3 years ago

8 0

Answer:

1300 cm 3

Explanation:

Phoenix [80]3 years ago

3 0

Answer:

The volume of the gas at given temperature is $1300 cm^3$

Explanation:

$P_1$ = initial pressure of gas = 1 atm

$T_1$ = initial temperature of gas = $0^oC=273.15 K$

$V_1$ = initial volume of gas = $310 cm^3 = 310 mL = 0.310 L$

( $1 cm^3= 1mL$ , 1 mL = 0.001 L)

$P_1V_1=nRT_1$ ..[1]

$P_2$ = final pressure of gas = 2.1 atm

$T_2$ = final temperature of gas = $2,200^oC=273+2200 K=2473.15 K$

$V_2$ = final volume of gas = ?

$P_2V_2=nRT_2$ ..[2]

By dividing [1] and [2] we get combined gas equation :,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

$V_2=\frac{P_1V_1\times T_2}{T_1\times P_2}$

Now put all the given values in the above equation, we get:

$V_2=\frac{1 atm\times 0.310 L\times 2473.15 K}{273.15 K\times 2.1 atm}$

$V_2=1.3 L=1300 mL= 1300 cm^3$

The volume of the gas at given temperature is $1300 cm^3$

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Explanation: -

a) The element Cr with negative reduction potential will lose electrons undergo oxidation and thus act as anode.The element Au with positive reduction potential will gain electrons undergo reduction and thus acts as cathode.

At cathode: $Au{3+}+3e^-\rightarrow Au$

At anode: $Cr\rightarrow Cr^{3+}+3e^-$

b) At cathode which is a positive terminal, reduction occurs which is gain of electrons.

At anode which is a negative terminal, oxidation occurs which is loss of electrons.

Gold acts as cathode ad Chromium acts as anode.

c) Overall balanced equation:

At cathode: $Au{3+}+3e^-\rightarrow Au$ (1)

At anode: $Cr\rightarrow Cr^{3+}+3e^-$ (2)

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