Answer:
(i) +3.
(ii) Mn.
Explanation:
Hello,
(i)
Based on the diatomic ion, we solve for the unknown oxidation state of carbon, assuming that the oxygen works with -2, by a change balance:
(ii)
We first must each ion's oxidation states as follows:
Then, for the reduction half reaction we identify the manganese as the element decreasing its oxidation state based on:
In addition, the carbon is oxidized from +3 to +4 (increase the oxidation state).
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When elements are heated/energized their electrons then absorb the energy and transition into a higher energy level known as the excited state. Then electrons then eventually fall back to their lowest state of energy or their ground state.
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Alloys are metallic compounds composed of one metal and one or more metal or non-metal element.
Alloys are useful because they allow us to maximize the desired properties within certain constraints in a way that is appropriate for the intended use.
Answer:
Strontium
Explanation:
In the periodic table, an element with two (2) valence electrons is found on group 2. Group 2 is a group of the periodic table that harbors element called ALKALINE EARTH METALS. As the name implies, they are metals that possess shiny and solid characteristics at room temperature.
Group 2 elements include the following: Beryllium (Be), Magnesium (Mg), Calcium (Ca), Strontium (Sr), barium (Ba), and radium (Ra). Based on the descriptive information in this question, the element being described is a GROUP 2 element. Based on the elements in the option, only STRONTIUM (Sr) is a group 2 element.
CO₂ has 4 + 2(6) = 16 valence electrons
CO₂ have linear molecular structures with a 180° bond angle. CO₂ is nonpolar because the individual bond dipoles cancel each other out
XeCl₂ has 8 + 2(7) = 22 valence electrons.
There are five pairs of electrons about the central Xe atom. The structure will be based on a trigonal bipyramid geometry. The most stable arrangement of the atoms in XeCl₂ is a linear molecular structure with a 180° bond angle. It is nonpolar because the Xe−Cl bond dipoles and lone pairs around Xe are arranged in such a manner that they cancel each other out.
(b)
SCl₆ is nonpolar because it has 6 bonding pairs and no lone pairs, giving it an octahedral shape. When you draw the vectors, you can see that the resultant is 0, making it nonpolar.
SCl₄ on the other hand is polar because it has 4 bonding pairs and one lone pair, giving it a trigonal pyramidal shape.
SCl₂ is also polar due to reasons similar to those in the case of SCl₄.