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Norma-Jean [14]

3 years ago

6

The Hoover Dam is 221 m tall and 379 m wide. Approximating it as a flat plate, determine the effective resultant force on the da

m and where it acts. What is the gage pressure at the bottom of the dam? Assume water has a constant density of 1000 kg m^3 .

1 answer:

IrinaVladis [17]3 years ago

3 0

Answer:

2165800 Pa

Explanation:

See it in the pic.

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Goshia [24]

Answer:

$\Delta p_{2} = 2\cdot \Delta p_{1}$

Explanation:

The pressure drop is directly proportional to the length of the pipe. Then, the new pressure drop is two time the previous one.

$\Delta p_{2} = 2\cdot \Delta p_{1}$

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Solid Isomorphous alloys strength

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Explanation:

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You are working in a lab where RC circuits are used to delay the initiation of a process. One particular experiment involves an

Ymorist [56]

Answer:

$t'_{1\2} = 6.6 sec$

Explanation:

the half life of the given circuit is given by

$t_{1\2} =\tau ln2$

where [/tex]\tau = RC[/tex]

$t_{1\2} = RCln2$

Given $t_{1\2} = 3 sec$

resistance in the circuit is 40 ohm and to extend the half cycle we added new resister of 48 ohm. the net resitance is 40+48 = 88 ohms

now the new half life is

$t'_{1\2} =R'Cln2$

Divide equation 2 by 1

$\frac{t'_{1\2}}{t_{1\2}} = \frac{R'Cln2}{RCln2} = \frac{R'}{R}$

$t'_{1\2} = t'_{1\2}\frac{R'}{R}$

putting all value we get new half life

$t'_{1\2} = 3 * \frac{88}{40} = 6.6 sec$

$t'_{1\2} = 6.6 sec$

7 0

3 years ago