A four-lane freeway (two lanes in each direction) is located on rolling terrain and has 12-ft lanes, no lateral obstructions wit
hin 6 ft of the pavement edges, and there are 2 ramps within 3 miles upstream of the segment midpoint and 3 ramps within 3 miles downstream of the segment midpoint. A weekday directional peak-hour volume of 1800 vehicles (familiar users) is observed, with 700 arriving in the most congested 15-min period. If a level of service no worse than C is desired, determine the maximum number of heavy vehicles that can be present in the peak-hour traffic stream.
Consider the freeway and traffic conditions described in Problem 6.3. If 180 of the 1800 vehicles observed in the peak hour were heavy vehicles (assume a 70%/30% SUT/TT split), what would the level of service of this freeway be on a 5-mi, 6% downgrade?
Consider the freeway and traffic conditions described in Problem 6.3. If 180 of the 1800 vehicles observed in the peak hour were heavy vehicles (assume a 70%/30% SUT/TT split), what would the level of service of this freeway be on a 5-mi, 6% downgrade?
1 answer:
Answer:
Check the explanation
Explanation:
FFS = Free-Flow Speed (km/h) BFFS = the Base Free-Flow Speed (km/h) fLS = the Adjustment for lane and shoulder widths less than 3.65 m and 1.80 m, respectively. fAPD = Adjustment for access points density (km/h) fm = Adjustment for proportion (km/h) 3.0 Results
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Answer:
27009.56 mm
Explanation:
Given:
Diameter of the aluminium alloy bar, d = 12.5 mm
Length of the bar, L = 27 m = 27 × 10³ mm
Tensile force, P = 3 KN = 3 × 10³ N
Elastic modulus of the bar, E = 69 GPa = 69 × 10³ N/mm²
Now,
for the uniaxial loading, the elongation or the change in length (δ) due to the applied load is given as:
where, A is the area of the cross-section
or
or
A = 122.718 mm²
on substituting the respective values in the formula, we get
or
δ = 9.56 mm
Hence, the length after the force is applied = L + δ = 27000 + 9.56
= 27009.56 mm
Answer:
Explanation:
z = number of atoms
M = Molar mass of zirconium
N = Avogadro’s number
Vc = volume of zirconium unit cell
d = density
z = 6 atoms per unit cell
M = 91.224 g/mol
N =
d =