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9966 [12]
3 years ago
14

A four-lane freeway (two lanes in each direction) is located on rolling terrain and has 12-ft lanes, no lateral obstructions wit

hin 6 ft of the pavement edges, and there are 2 ramps within 3 miles upstream of the segment midpoint and 3 ramps within 3 miles downstream of the segment midpoint. A weekday directional peak-hour volume of 1800 vehicles (familiar users) is observed, with 700 arriving in the most congested 15-min period. If a level of service no worse than C is desired, determine the maximum number of heavy vehicles that can be present in the peak-hour traffic stream.
Consider the freeway and traffic conditions described in Problem 6.3. If 180 of the 1800 vehicles observed in the peak hour were heavy vehicles (assume a 70%/30% SUT/TT split), what would the level of service of this freeway be on a 5-mi, 6% downgrade?

Engineering
1 answer:
guapka [62]3 years ago
7 0

Answer:

Check the explanation

Explanation:

FFS = Free-Flow Speed (km/h) BFFS = the Base Free-Flow Speed (km/h) fLS = the Adjustment for lane and shoulder widths less than 3.65 m and 1.80 m, respectively. fAPD = Adjustment for access points density (km/h) fm = Adjustment for proportion  (km/h) 3.0 Results

Kindly check the below image for the step by step explanation to the above question.

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Answer:

minimum flow rate provided by pump is 0.02513 m^3/s

Explanation:

Given data:

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We know that flow rate Q is given as

Q = A \times V

where A is Area

A =\frac{\pi}{4} \times (40\times 10^{-3})^2 = 1.256\times 10^{-3} m^2

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minimum flow rate provided by pump is 0.02513 m^3/s

5 0
3 years ago
A segment of four-lane freeway (two lanes in each direction) has a 3% upgrade that is 1500 ft long followed by a 1000-ft 4% upgr
Dennis_Churaev [7]

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Explanation:

Find the provided attachments for explanation

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Answer:

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