Part A:
Given a square with sides 6 and x + 4. Also, given a rectangle with sides 2 and 3x + 4
The perimeter of the square is given by 4(x + 4) = 4x + 16
The area of the rectangle is given by 2(2) + 2(3x + 4) = 4 + 6x + 8 = 6x + 12
For the perimeters to be the same
4x + 16 = 6x + 12
4x - 6x = 12 - 16
-2x = -4
x = -4 / -2 = 2
The value of x that makes the <span>perimeters of the quadrilaterals the same is 2.
Part B:
The area of the square is given by
The area of the rectangle is given by 2(3x + 4) = 6x + 8
For the areas to be the same
Thus, there is no real value of x for which the area of the quadrilaterals will be the same.
</span>
If you are asking if (2,14) would be a point on the line, it would not because:
14≠5*2+10
Hope this helps :)
Answer:
3 x = 2 = 2 x = 1 = 2 = 5 X =
Step-by-step explanation:
Use the given functions to set up and simplify
5X.
im pretty sure this is right, butt if its not im sorry <3
A. 4:5. Every time he gets 4 apples (the number that comes first) 5 oranges follow