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juin [17]
2 years ago
10

What is the tangential velocity of a record player which makes 11 revolutions in 20 seconds?

Physics
1 answer:
Vsevolod [243]2 years ago
3 0
What is the tangential velocity of a record player which makes 11 revolutions in 20 seconds? Help hello
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Calculate the refractive index for a substance where the angle of incidence is 300 , the angle of refraction is 600 , and the re
Sophie [7]

Answer:

η₁ = 2.6

Explanation:

Here, we will use snell's law to calculate the refractive of the substance:

\frac{\eta_2}{\eta_1} = \frac{Sin\theta_1}{Sin\theta_2}

where,

η₁ = refractive index of first substance = ?

η₂ = refractive index of second substance = 1.5

θ₁ = angle of incidence = 30°

θ₂ = angle of refraction = 60°

Therefore,

\frac{1.5}{\eta_1} = \frac{Sin\ 30^0}{Sin\ 60^0}

<u>η₁ = 2.6</u>

7 0
2 years ago
Two rocks, A and B, are thrown horizontally from the top of a cliff. Rock A has an initial speed of 10 meters per second and roc
maria [59]

Answer:

i need help

Explanation:

4 0
1 year ago
A 1502.7 kg car is traveling at 33.1 m/s when
Bond [772]

By definition of average acceleration,

<em>a</em> = (20 m/s - 33.1 m/s) / (4.7 s) ≈ -2.78 m/s²

Vertically, the car is in equilibrium, so the net force is equal to the friction force in the direction opposite the car's motion:

∑ <em>F</em> = (1502.7 kg) (-2.78 m/s²) ≈ -4188.38 N ≈ -4200 N

If you just want the magnitude, drop the negative sign.

5 0
3 years ago
Find the range of a projectile launched at an angle of 30° with an initial velocity of 20m/s.​
Tems11 [23]

Answer:

<em>The range is 35.35 m</em>

Explanation:

<u>Projectile Motion</u>

It's the type of motion that experiences an object projected near the Earth's surface and moves along a curved path exclusively under the action of gravity.

Being vo the initial speed of the object, θ the initial launch angle, and g=9.8m/s^2 the acceleration of gravity, then the maximum horizontal distance traveled by the object (also called Range) is:

\displaystyle d={\frac  {v_o^{2}\sin(2\theta )}{g}}

The projectile was launched at an angle of θ=30° with an initial speed vo=20 m/s. Calculating the range:

\displaystyle d={\frac  {20^{2}\sin(2\cdot 30^\circ )}{9.8}}

\displaystyle d={\frac  {400\sin(60^\circ )}{9.8}}

d=35.35\ m

The range is 35.35 m

7 0
3 years ago
Use the vocabulary in the Word Bank to complete the following explanation.
ahrayia [7]
Where’s the vocabulary?
5 0
3 years ago
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