Answer:
Average speed, As = 2.2 [m/s]
Explanation:
To solve these types of problems we must remember that the average of the speeds is determined by dividing the distance over time.
With the first speed and the time of 6 [s] we can calculate the distance.
V = x/t
where:
x = distance [m]
V = velocity = 1.1 [m/s]
t = time = 6 [s]
x1 = V*t
X1 = 1.1*6
X1 = 6.6 [m]
Now with the second velocity and 6 [s], we can calculate the second distance.
X2 = 3.3*6
X2 = 19.8 [m]
Now we have to calculate the average speed. The total distance is x = x1 +x2
X = 19.8 + 6.6 = 26.4 [m]
and the total time is 12 [s]
Therefore:
As = 26.4/12
As = 2.2 [m/s]
you can use one of your 5 senses to make _____ during an inquiry activity.
sound
Answer:
(a)

(b)
1120 N
Explanation:
Change in velocity,
is given by subtracting the initial velocity from the final velocity and expressed as 
Where v represent the velocity and subscripts f and i represent final and initial respectively. Since the ball finally comes to rest, its final velocity is zero. Substituting 0 for final velocity and the given figure of 8 m/s for initial velocity then the change in velocity is given by

To find
then we substitute 7 kg for m and -8 m/s for
therefore 
(b)
The impact force, F is given as the product of mass and acceleration. Here, acceleration is given by dividing the change in velocity by time ie

Substituting t with 0.05 s then 
Since F=ma then substituting m with 7 Kg we get that F=7*-160=-1120 N
Therefore, the impact force is equivalent to 1120 N
Answer:
0.8
Explanation:
The two spheres have the same potential, V.
Let the radius of the larger sphere be R and the radius of the smaller sphere be r,
=> R = 4r
Let the charge on the smaller sphere be q. Hence, the larger sphere will have charge Q - q.
The potential of the smaller sphere will be:

The potential of the larger sphere will be:

Inputting R = 4r,

Since
,

=> Q - q = 4q
=> 5q = Q
q = 0.2Q
The fraction of the charge Q that rests on the smaller sphere is 0.2
The charge of the larger sphere is:
Q - q = Q - 0.2Q = 0.8Q
∴ The fraction of the total charge Q that rests on the larger sphere is 0.8