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Romashka [77]
3 years ago
14

Determine the minimum angle at which a frictionless road should be banked so that a car traveling at 20.0 m/s can safely negotia

te the curve if the radius of the curve is 200.0 m.

Physics
1 answer:
EleoNora [17]3 years ago
3 0

Answer:

Minimum angle at which frictionless road should be banked is 11.53°

Explanation:

Consider the figure below to understand the banking curve. θ is  minimum angle at which frictionless road should be banked.

Forces acting along x-axis:

F_{N}sin\theta=\frac{mv^{2}}{R}---(1)\\\\

Forces acting along y-axis:

F_{N}cos\theta-mg=0---(2)\\\\

Dividing (1) and (2)

\frac{F_{N}sin\theta}{F_{N}cos\theta}=\frac{\frac{mv^{2}}{R}}{mg}\\\\tan\,\theta=\frac{v^{2}}{rg}\\\\v=20\,m/s,\,r=200\,m\\\\tan\,\theta=\frac{(20)^{2}}{(200)(9.8)}\\\\tan\,\theta=0.204\\\\\theta=tan^{-1}(0.204)\\\theta=11.53^{o}\\

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Two particles P and Q each moves towards ther along Straight Line (M)(N), 51m long. P starts from M with velocity 5m/s and const
bagirrra123 [75]

The time required by the particles are as follows:

a. t = 1.5 seconds

b. t = 3 seconds

c. t = 0.4 seconds

<h3>What is the time required?</h3>

The time required for the particles to be at several distances apart is calculated using the equation of motion given below:

S = ut + \frac{1}{2}at^{2}

a) Time required to be 30 m apart:

Assuming the distance covered by P is S1 and distance covered by Q is S2.

S1 + S2 = 51 - 30

S1 + S2 = 21

Substituting the values of velocity and acceleration in the equation of motion above:

5t + 1/2t^2 + 6t + 3t^2 = 21

2t^2 + 11t - 21 = 0

Solving for time, t by factorization, t = 1.5 seconds

b) Time required to meet:

Assuming the distance covered by P is S1 and distance covered by Q is S2.

S1 + S2 = 51

Substituting the values of velocity and acceleration in the equation of motion above:

5t + 1/2t^2 + 6t + 3t^2 = 51

2t^2 + 11t - 51 = 0

Solving for time, t by factorization, t = 3 seconds

c) Time required for velocity of P is ¾ of the velocity of Q:

Using the equation of motion: V = u + at

Vp = 3/4 Vq

4Vp= 3Vq

Substituting the values:

4(5 + t) = 3(6 + 3t)

5t = 2

t = 0.4 seconds

Learn more about distance, velocity and acceleration at: brainly.com/question/14344386

#SPJ1

7 0
2 years ago
Investing in yourself and your career often requires you to “play it safe”.
SashulF [63]

i'd say false, is this for health or lifeskills?

8 0
3 years ago
This woman is riding a bicycle down a hill at a constant speed and in a straight line. Which change will increase the speed of t
Marina86 [1]

Answer: Um I would say maybe b

Explanation:

4 0
3 years ago
Read 2 more answers
Two protons are 9.261 fm apart. (1 fm= 1 femtometer = 1 x 10^-15 m.) What is the ratio of the electric force to the gravitationa
Strike441 [17]

Answer:

1.24\times 10^{36}

Explanation:

q = magnitude of charge on each proton = 1.6 x 10⁻¹⁹ C

m = mass of each proton = 1.67 x 10⁻²⁷ kg

r = distance between the two protons = 1 x 10⁻¹⁵ m

Electric force between the two protons is given as

F_{e} = \frac{kq^{2}}{r^{2}}

F_{e} = \frac{(9\times 10^{9})(1.6\times 10^{-19})^{2}}{(1\times 10^{-15})^{2}}

F_{e} = 230.4 N

Gravitational force between the two protons is given as

F_{g} = \frac{Gm^{2}}{r^{2}}

F_{g} = \frac{(6.67\times 10^{-11})(1.67\times 10^{-27})^{2}}{(1\times 10^{-15})^{2}}

F_{g} = 1.86\times 10^{-34} N

Ratio is given as

Ratio =\frac{F_{e}}{F_{g}}

Ratio =\frac{230.4}{1.86\times 10^{-34}}

Ratio = 1.24\times 10^{36}

3 0
3 years ago
Read 2 more answers
(a) and (b) ??Thanks <br>HELP <br>d8 =1​
garri49 [273]

Explanation:

(a) You can solve this using kinematics or energy.

Using kinematics:

a = F/m = 90 N / 4 kg = 22.5 m/s²

v₀ = 0 m/s

Δx = 5 m

Find: v

v² = v₀² + 2aΔx

v² = (0 m/s)² + 2 (22.5 m/s²) (5 m)

v = 15 m/s

Using energy:

W = ΔKE

Fd = ½ mv²

(90 N) (5 m) = ½ (4 kg) v²

v = 15 m/s

(b) ΔU = mg Δh

ΔU = (4 kg) (9.8 m/s) (12 m sin 40° − 15 m)

ΔU = -290 J

W = ΔU = -290 J

7 0
2 years ago
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