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PSYCHO15rus [73]
2 years ago
15

What is the purpose of light energy?

Chemistry
1 answer:
zimovet [89]2 years ago
8 0
The sun gives off light energy to help plants photosynthesize and make food
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when an electron gets closer to the nucleus does the attraction or repulsion grow weaker or stronger?
klasskru [66]

Answer:

Weaker

Explanation:

Since the charges on nucleus and electron are opposite in nature, an attractive force exists between them. It is true in generally, that when objects are made to move closer together in the direction of an attractive force, potential energy decreases (and increases whenever attracting objects are force to move apart).

6 0
3 years ago
Hypothesis
notsponge [240]

Answer:

1) The problem is that you get a salty taste in our mouth when you drink orange juice after brushing our teeth.

Explanation:

8 0
3 years ago
Using the equation, C5H12 + 8O2 Imported Asset 5CO2 + 6H2O, if 2 moles of pentane (C5H12) were supplied, and an unlimited amount
Kamila [148]

12 moles of water H₂O are produced from the combustion of pentane.

Explanation:

We have the following combustion of pentane (C₅H₁₂):

C₅H₁₂ + 8 O₂ → 5 CO₂ + 6 H₂O

Knowing the chemical reaction we devise the following reasoning:

if         1 moles of pentane C₅H₁₂ produces 6 moles of water H₂O

then    2 moles of pentane C₅H₁₂ produces X moles of water H₂O

X = (2 × 6) / 1 = 12 moles of water H₂O

Learn more about:

combustion of organic compounds

brainly.com/question/7295137

brainly.com/question/884053

#learnwithBrainly

7 0
2 years ago
Consider the following reaction: CH3OH(g)⇌CO(g)+2H2(g) Part A Calculate ΔG for this reaction at 25 ∘C under the following condit
kati45 [8]

<u>Answer:</u> The \Delta G of the reaction at given temperature is -12.964 kJ/mol.

<u>Explanation:</u>

For the given chemical reaction:

CH_3OH(g)\rightleftharpoons CO(g)+2H_2(g)

The expression of K_p for the given reaction:

K_p=\frac{(p_{CO})\times (p_{H_2}^2)}{p_{CH_3OH}}

We are given:

p_{CO}=0.140atm\\p_{H_2}=0.180atm\\p_{CH_3OH}=0.850atm

Putting values in above equation, we get:

K_p=\frac{(0.140)\times (0.180)^2}{0.850}\\\\K_p=5.34\times 10^{-3}

To calculate the Gibbs free energy of the reaction, we use the equation:

\Delta G=\Delta G^o+RT\ln K_p

where,

\Delta G = Gibbs' free energy of the reaction = ?

\Delta G^o = Standard gibbs' free energy change of the reaction = 0 J (at equilibrium)

R = Gas constant = 8.314J/K mol

T = Temperature = 25^oC=[25+273]K=298K

K_p = equilibrium constant in terms of partial pressure = 5.34\times 10^{-3}

Putting values in above equation, we get:

\Delta G=0+(8.314J/K.mol\times 298K\times \ln(5.34\times 10^{-3}))\\\\\Delta G=-12963.96J/mol=-12.964kJ/mol

Hence, the \Delta G of the reaction at given temperature is -12.964 kJ/mol.

5 0
3 years ago
What are the intermolecular forces present in acetone?
notka56 [123]

Answer:

dipole-dipole interactions.

Explanation:

hope this helps

plz mark brainliest

3 0
2 years ago
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