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3 years ago

The chemical equation below shows the formation of aluminum oxide (Al2O3) from aluminum (Al) and oxygen (O2).

Chemistry

1 answer:

Rufina [12.5K]3 years ago

4 0

Answer:

Mass = 182.4 g

Explanation:

Given data:

Number of moles of Al₂O₃ = 3.80 mol

Mass of oxygen required = ?

Solution:

Chemical equation:

4Al + 3O₂ → 2Al₂O₃

Now we will compare the moles of aluminum oxide and oxygen.

Al₂O₃ : O₂

2 : 3

3.80 : 3/2×3.80 = 5.7

Mass of oxygen:

Mass = number of moles × molar mass

Mass = 5.7 mol × 32 g/mol

Mass = 182.4 g

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Sedbober [7]

$\Large \text{1)}$

$\textbf{Use the formula and substitute the values}$

$\displaystyle 0.3\ mol/L = \frac{n \ mol}{10 \times 10^{-3}\ L}$

$\textbf{Solve for the number of moles}$

$n = 0.003\ mol$

$\textbf{Calculate final volume }$

$40+10=50\ mL$

$\textbf{Number of moles remains same. Solve for concentration}$

$\displaystyle C=\frac{0.003\ mol}{50 \times 10^{-3}\ L} =0.06\ mol/L$

$\Large \text{2)}$

$\displaystyle DF=\frac{V_f}{V_i}$

$\displaystyle DF=\frac{50}{10}=5$

3 0

3 years ago

Calcium carbide reacts with water to produce acetylene gas according to the following equation: CaC2(s) + 2H2O(l)C2H2(g) + Ca(OH

mars1129 [50]

Answer : The number of moles of $CaC_2$ reacted was, 0.214 moles.

Explanation :

First we have to calculate the mole of $C_2H_2$ gas.

Using ideal gas equation:

$PV=nRT$

where,

P = Pressure of $C_2H_2$ gas = 748 mmHg - 23.8 mHg = 724.2 mmHg = 0.953 atm (1 atm = 760 mmHg)

V = Volume of $C_2H_2$ gas = 5.50 L

n = number of moles $C_2H_2$ = ?

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of $C_2H_2$ gas = $25^oC=273+25=298K$

Putting values in above equation, we get:

$0.953atm\times 5.50L=n\times (0.0821L.atm/mol.K)\times 298K$

$n=0.214mol$

Now we have to calculate the moles of $CaC_2$

The balanced chemical reaction is:

$CaC_2(s)+2H_2O(l)\rightarrow C_2H_2(g)+Ca(OH)_2(aq)$

From the balanced chemical reaction we conclude that,

As, 1 mole of $C_2H_2$ gas produced from 1 mole of $CaC_2$

So, 0.214 mole of $C_2H_2$ gas produced from 0.214 mole of $CaC_2$

Therefore, the number of moles of $CaC_2$ reacted was, 0.214 moles.

4 0

3 years ago

All acids and alkais are<br> dangerous to us to what extent is that statment true

AveGali [126]

Answer: Most acids and Alkais are dangerous however not all are dangerous.

Explanation:

8 0

3 years ago

What happen when calcium carbonate react with zinc

GarryVolchara [31]

Answer:

answer is rust is formed

3 0

3 years ago

If 9.5 × 10²⁵ molecules of CO₂ are produced in a combustion reaction, what is the mass in kg of CO₂ that is produced?

Leno4ka [110]

Answer:

6.9428 kg of CO2

Explanation:

1) Use Avogadro's number that states 1 mole = 6.022 x 10^23 particles. Convert 9.5 x 10^25 molecules into moles.

9.5 x 10^25 CO2 molecules $x\frac{1 mole CO2}{6.022 x 10^23}$ = 157.75 moles CO2

2) Convert 157.75 moles of CO2 into grams. CO2's molar mass is 44.01g.

$157.75moles CO2$ $x \frac{44.01g/mol}{1 mole CO2}$ = 6942.79g

3) Convert 6942.79 grams into kilograms (divide by 1000):

6.9428 kg

4 0

3 years ago