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2 years ago

How could you increase the potential energy of the roller coaster shown below?

Physics

2 answers:

uysha [10]2 years ago

5 0

It's choice A and B. PE=mgh

Zinaida [17]2 years ago

4 0

Your answer would be,

Choice A only. (A. Increase the height of the hill.)

Hope I helped. - HMOMHW (HelpMahOnMahHomeWork)

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At what point in its swing is potential energy a maximum? E B D A C

cestrela7 [59]

I think the answer is A.

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3 years ago

When a loop of current-carrying wire turns continuously in a magnetic field, a _________ is created.

Brrunno [24]

A solenoid is created

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2 years ago

the force that gravitation exerts upon a body, equal to the mass of the body times the local acceleration of gravity

PIT_PIT [208]

The force that gravitation exerts upon a body, equal to the mass of the body times the local acceleration of gravity is known as weight.

Weight is the force of gravity acting on a body.

The formula is :

W =mg

Here,

W is the weight or force acting on the body. m is the mass of the body, and g is the gravitational acceleration.

Since weight is also a force, so its SI unit is also newton. The value of weight varies from place to place depending on the gravity. Its value can also be equal to zero.

If you need to learn about the difference between mass and weight, click here

brainly.com/question/23876249?referrer=searchResults

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8 0

1 year ago

A car is designed to get its energy from a rotating

nydimaria [60]

Answer:

(a). The kinetic energy stored in the fly wheel is 46.88 MJ.

(b). The time is 1.163 hours.

Explanation:

Given that,

Radius = 1.50 m

Mass = 475 kg

Power $P= 15.0 hp = 15.0\times746=11190 watt$

Rotational speed = 4000 rev/min

We need to calculate the moment of inertia

Using formula of moment of inertia

$I=\dfrac{1}{2}mr^2$

Put the value into the formula

$I=\dfrac{1}{2}\times475\times(1.50)^2$

$I=534.375\ kg m^2$

(a). We need to calculate the kinetic energy stored in the fly wheel

Using formula of K.E

$K.E=\dfrac{1}{2}I\omega^2$

Put the value into the formula

$K.E = \dfrac{1}{2}\times534.375\times(4000\times\dfrac{2\pi}{60})^2$

$K.E=46880620.9\ J$

$K.E =46.88\times10^{6}\ J$

$K.E =46.88\ MJ$

(b). We need to calculate the length of time the car could run before the flywheel would have to be brought backup to speed

Using formula of time

$t=\dfrac{46.88\times10^{6}}{11190}$

$t=4189.45\ sec$

$t=1.163\ hours$

Hence, (a). The kinetic energy stored in the fly wheel is 46.88 MJ.

(b). The time is 1.163 hours.

3 0

3 years ago

How could you determine the injuries or ill person in a secondary assessment?

lana66690 [7]

Answer:

just in internet tho

6 0

2 years ago

Read 2 more answers