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3 years ago

What is the closest of a measurement to the actual value being measured

1 answer:

5 0

The Answer is Accuracy.
Accuracy is the closest of a measurement to the actual value being measured.
The condition of being true or correct is accuracy and it is a term which is used in daily life, many fields of science. it is the degree of closeness of the measurement or values between the measurements of the quantity and the actual or true value, there is may be inaccuracy which is also due to many factors.

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Through which one of the following mediums is the velocity of a sound wave the greatest?

Colt1911 [192]

Answer: C. Steel

Explanation: When a sound wave travels through a solid body consisting

of an elastic material, the velocity of the wave is relatively

high. For instance, the velocity of a sound wave traveling

through steel (which is almost perfectly elastic) is about

5,060 meters per second. On the other hand, the velocity

of a sound wave traveling through an inelastic solid is

relatively low. So, for example, the velocity of a sound wave

traveling through lead (which is inelastic) is approximately

1,402 meters per second.

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3 years ago

A 2,000 kg railroad car is coasting on a track at a constant velocity of 20 m/s. As the car coasts under a loading ramp, a 500 k

BlackZzzverrR [31]

Answer:

the car with the hay should slow to 16m/s if the bale of hay is dropped into it.

3 0

3 years ago

Why does ice float on water?

WITCHER [35]

Explanation:

Ice floats on water because it's alil water compacted into 1 shape which is heavier, ice is also a solid at 1st so solid things also can float on water

6 0

3 years ago

A train accelerates from a station with a = 1.841m/s ? Upon reaching a speed of 23.52m/s the train travels at a constant velocit

scZoUnD [109]

Answer:

63.29s

Explanation:

Firstly calculate the time taken to reach 23.52m/s

;use the formula...v = u + at

23.52 = 0 + 1.841t

then obtain...t = 12.78s

Then calculate the time for the last part of the journey...where the train slows down...

use the formula that is above...

0 = 23.52 - 2t...(negative for deceleration)

then obtain....t = 11.76s

Then we know that the total area under the graph of u against t..is equal to 1200m

For the first triangle(first part of the journey...where the train accelerates)

(23.52 × 12.78)÷2 = 150.3m

Then for the constant velocity part...a rectangle...

23.52 × f.....where f represents the time taken by the train having constant velocity.

...= 23.52fm

Then for the last part of the journey...the deceleration part..a triangle

(23.52 × 11.76)÷ 2 = 138.3m

Then....we add all the obtained distances and equate to 1200m so that we can obtain time (f)

138.3 + 150.3 + 23.52f = 1200

where f = 38.75s

Then total time for the whole journey of the train...

38.75 + 11.76 + 12.78

;Ans = 63.29s

3 0

3 years ago

A 3 kg mass is travelling in a circle of 0.1 m radius with a speed of 2 m/s. What is the centripetal acceleration?

BaLLatris [955]

a = v² / R = (2 m/s)² / (0.1 m) = 40 m/s²

7 0

3 years ago