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3 years ago

10

What is the closest of a measurement to the actual value being measured

1 answer:

Snowcat [4.5K]3 years ago

5 0

The Answer is Accuracy.
Accuracy is the closest of a measurement to the actual value being measured.
The condition of being true or correct is accuracy and it is a term which is used in daily life, many fields of science. it is the degree of closeness of the measurement or values between the measurements of the quantity and the actual or true value, there is may be inaccuracy which is also due to many factors.

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Read 2 more answers

A jet aircraft is traveling at 262 m/s in hor-

NeTakaya

Solution :

Speed of the air craft, $S_a$ = 262 m/s

Fuel burns at the rate of, $S_b$ = 3.92 kg/s

Rate at which the engine takes in air, $S_{air}$ = 85.9 kg/s

Speed of the exhaust gas that are ejected relative to the aircraft, $S_{exh}$ =921 m/s

Therefore, the upward thrust of the jet engine is given by

$F=S_{air}(S_{exh}-S_a)+(S_b \times S_{exh})$

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= 4862635.79 + 3610.32

= $4.8 \times 10^6 \ N$

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3 years ago

The charge density of a uniformly charged disk 0.420 m in diameter is 2.92 ✕ 10−2 C/m2. What is the magnitude of the electric fi

iragen [17]

Answer:

E = {(Charge Density/2e0)*(1 - [z/(sqrt(z^2 - R^2))]}

R is radius = Diameter/2 = 0.210m.

At z = 0.2m,

Put z = 0.2m, and charge density = 2.92 x 10^-2C/m2, and constant value e0 in the equation,

E can be calculated at distance 0.2m away from the centre of the disk.

Put z = 0.3m and all other values in the equation,

E can be calculated at distance 0.3m away from the centre of the disk

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3 years ago

At what position in its elliptical orbit is the speed of a planet a maximum? when it is closest to the sun when it is farthest f

Phantasy [73]

Answer:

1.when it is closest to the sun

2.when it is midway between its farthest

Explanation:

According to the law of Kepler's

T ² ∝ r³

T=Time period

r=semi major axis

We also know that time period T given as

$T=\dfrac{2\pi r}{v}$

v=Speed

$v=\dfrac{2\pi r}{T}$

$v\alpha \dfrac{r}{T}$

$v\alpha \dfrac{r}{T}$

$v^2\alpha \dfrac{r^2}{T^2}$

$v^2\alpha \dfrac{r^2}{r^3}$

$v^2\alpha \dfrac{1}{r}$

$v\alpha \dfrac{1}{\sqrt{r}}$

So we can say that ,when r is more then the speed will be minimum and when r is low then speed will be maximum.

7 0

3 years ago