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Finger [1]
3 years ago
10

What is the closest of a measurement to the actual value being measured

Physics
1 answer:
Snowcat [4.5K]3 years ago
5 0
The Answer is Accuracy.
Accuracy is the closest of  a measurement to the actual value being measured.
The condition of being true or correct is accuracy and it is a term which is used in daily life, many fields of science. it is the degree of closeness of the measurement or values between the measurements of the quantity and the actual or true value, there is may be inaccuracy which is also due to many factors.
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An experiment is performed to determine how bats capture insects in the dark. A pair of microphones are set up on either end of
Masteriza [31]

Answer:

Explanation:

We shall apply Doppler's effect here .

original frequency = 79.79 kHz

apparent frequency due to movement of source ( bat ) = 81.63 Hz

Let the velocity of bat be v .

expression for apparent frequency can be given as follows

n = \frac{n_0V}{V-v}

n is apparent frequency , n₀ is original frequency , V is velocity of light and v is velocity of source of sound

Putting the values

81.63 = \frac{79.79\times 340}{340-v}

340-v = 332.33

v = 7.67 m /s

velocity of bat is 7.67 m /s .

7 0
3 years ago
True or False. You do not need to stretch each side of your body.
Veronika [31]

Answer:

True

Explanation:

5 0
3 years ago
Read 2 more answers
3. A block with a force of the Earth of -300. N is moved at constant velocity over a horizontal surface by a force of +50.0 N ap
KIM [24]

Answer:

-6

Explanation:

FRICTIONAL force=-300N,NORMAL REACTION,R=+50.0

Ú=F/R

=-300/+50.0

=-6

3 0
2 years ago
Can anyone tell me how to read a micrometer screw gauge I want very clear instructions.
Natalka [10]

Explanation:

Things you need to know:

Accuracy refers to the maximum error encountered when a particular observation is made.

Error in measurement is normally one-half the magnitude of the smallest scale reading.

Because one has to align one end of the rule or device to the starting point of the measurement, the appropriate error is thus twice that of the smallest scale reading.

Error is usually expressed in at most 1 or 2 significant figures.

Tape

Equipment: It is made up of a long flexible tape and can measure objects or places up to 10 – 50 m in length. It has markings similar to that of the rigid rule. The smallest marking could be as small as 0.1 cm or could be as large as 0.5 cm or even 1 cm.

How to use: The zero-mark of the measuring tape is first aligned flat to one end of the object and the tape is stretched taut to the other end, the reading is taken where the other end of the object meets the tape.

Ruler

Equipment: It is made up of a long rigid piece of wood or steel and can measure objects up to 100 cm in length. The smallest marking is usually 0.1 cm.

How to use: The zero-end of the rule is first aligned flat with one end of the object and the reading is taken where the other end of the object meets the rule.

Vernier Caliper

Equipment: It is made up of a main scale and a vernier scale and can usually measure objects up to 15 cm in length. The smallest marking is usually 0.1 cm on the main scale.

It has:

a pair of external jaws to measure external diameters

a pair of internal jaws to measure internal diameters

a long rod to measure depths

How to use: The jaws are first closed to find any zero errors. The jaws are then opened to fit the object firmly and the reading is then taken.

Micrometer Screw Gauge

Equipment: It is made up of a main scale and a thimble scale and can measure objects up to 5 cm in length. The smallest marking is usually 1 mm on the main scale (sleeve) and 0.01 mm on the thimble scale (thimble). The thimble has a total of 50 markings representing 0.50 mm.

It has:

an anvil and a spindle to hold the object

a ratchet on the thimble for accurate tightening (prevent over-tightening)

How to use: The spindle is first closed on the anvil to find any zero errors ( use the ratchet for careful tightening). The spindle is then opened to fit the object firmly (use the ratchet for careful tightening) and the reading is then taken.

5 0
3 years ago
A stone with a mass m is dropped from an airplane that has a horizontal velocity v at a height h above a lake. If air resistance
seropon [69]

Answer: Option B. R = (1/2)gt^2

Explanation:

S = R (horizontal distance)

V^2 = 2gS

V^2 = 2gR

R = V^2 / 2g

But V = gt

R = (gt)^2 / 2g

R = (g^2 x t^2) / 2g

R = gt^2 / 2

But t^2 = 2h/g

R = ( g x 2h/g) / 2

R = h

But h = (1/2)gt^2

R = h = (1/2)gt^2

4 0
3 years ago
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