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viktelen [127]
3 years ago
5

Hello everyone. XxUnknownUserXx needs to be stopped he's abusing a girl named Rosa. Anyone that is friends that lives close to h

er, tell someone. Everybody pass this on he needs to be stopped! PLEASE REPOST THIS COMMENT!!! IT IS CRUCIAL WE TAKE HIM DOWN!!!!
Physics
2 answers:
Natali5045456 [20]3 years ago
4 0

Answer: I will spread this to people! Thank you for telling me.

d1i1m1o1n [39]3 years ago
3 0

Answer:

YES THANK YOU EVERYONE SPREAD THE WORD

Explanation:

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Consider a sound wave moving through the air modeled with the equation s(x, t) = 5.00 nm cos(60.00 m−1x − 18.00 ✕ 103 s−1t). Wha
GaryK [48]

Answer:

Shortest time = 58.18 × 10^(-6) s

Explanation:

We are given;

s(x,t) = 5.00 nm cos((60.00 m^(−1)x) − (18.00 X 10³ s^(−1)t))

Let us set x = 0 as origin.

Now, for us to find the time difference, we need to solve 2 equations which are;

s(x,t) = 5.00 nm cos((60.00 m^(−1)x) − (18.00 X 10³ s^(−1)t1))

And

s(x,t) = 5.00 nm cos((60.00 m^(−1)x) − (18.00 X 10³ s^(−1)t2))

Now, since the wave starts from maxima at time at t = 0, the required time would be the difference (t2 - t1)

Thus, the solutions are;

t1 = (1/(18 × 10³)) cos^(-1) (2.5/5)

And

t2 = (1/(18 × 10³)) cos^(-1) (-2.5/5)

Angle of the cos function is in radians, thus;

t1 = 58.18 × 10^(-6) s

t2 = 116.36 × 10^(-6) s

So,

Required time = t2 - t1 = (116.36 × 10^(-6) s) - (58.18 × 10^(-6) s) = 58.18 × 10^(-6) s

4 0
3 years ago
A plane flies along a straight line path after taking off, and it ends up 210 km farther east and 90.0 km farther north, relativ
Lapatulllka [165]
<span>A plane flies along a straight line path after taking off, and it ends up 210 km farther east and 90.0 km farther north, relative to where it started. we should use Pythagoras theorem for this. distance^2= 210^2 + 90^2.=228.47km, when rounding off this would comes around 230 km</span>
8 0
3 years ago
Read 2 more answers
Tell the different energy transformations that happen in each of these items
Alik [6]

Answer:

Television: Electricity to light Toaster: Electricity to Heat

Explanation:

ENERGYY

3 0
3 years ago
jack be nimble jack be quick jack jumped over the candlestick with a velocity of 5.0 m/s at an angle of 30.0 degrees to horizont
Mrrafil [7]

Answer:

No

Explanation:

The vertical component of Jack's initial velocity is:

5.0

⋅

sin

30

∘

=

5.0

⋅

1

2

=

2.5

m/s

With gravitational acceleration

9.8

m/s

2

, he will reach the highest point of his trajectory after:

2.5

9.8

≈

0.255

s

The average vertical component of his velocity in that

0.255

s

will be:

1

2

⋅

2.5

=

1.25

m/s

So the highest point of his trajectory will be:

0.255

⋅

1.25

≈

0.32

m

So he will pass approximately

7

cm

above the top of the candle.

The horizontal component of his velocity will be a constant:

5.0

⋅

cos

30

∘

=

5.0

⋅

√

3

2

≈

4.33

m/s

So Jack's trajectory will be substantially longer than it is high and he will spend little time anywhere near above the candle.

4 0
3 years ago
A 60kg student traveling in a 1000kg car with a constant velocity has a kinetic energy of 1.2 x 10^4 J. What is the speedometer
777dan777 [17]

Answer:

17.64 km/h

Explanation:

mass of car, m = 1000 kg

Kinetic energy of car, K = 1.2 x 10^4 J

Let the speed of car is v.

Use the formula for kinetic energy.

K = \frac{1}{2}mv^{2}

By substituting the values

1.2\times 10^{4} = \frac{1}{2}\times 1000\times v^{2}

v = 4.9 m/s

Now convert metre per second into km / h

We know that

1 km = 1000 m

1 h = 3600 second

So, v = \left (\frac{4.9}{1000}   \right )\times \left ( \frac{3600}{1} \right )

v = 17.64 km/h

Thus, the reading of speedometer is 17.64 km/h.

4 0
3 years ago
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