Because of friction, net work on the crate is less. ∆KE = Net work = net force x distance = (100 N – 70 N)(10 m) = 300 J.
Answer:
d = ( -0.3 , 0.7 ) miles
Explanation:
The complete question is as follows:
" Take the north direction as the positive y direction and east as positive x. The origin is still where the student starts biking. Let d⃗ N be the displacement vector corresponding to the first leg of the student's trip. Express d⃗ N in component form.
Express your answer as two numbers separated by a comma (e.g., 1.0,2.0). By convention, the x component is written first.
A student bikes to school by traveling first dN = 0.800 miles north, then dW = 0.300 miles west, and finally dS = 0.100 miles south. "
Solution:
- The displacement vector d N is vector sum of all journeys. We will express +x as +i and +y as +j. Then displacement vector is given by:
d = dN + dW + dS
d = 0.8 j - 0.3 i - 0.1 j
d = - 0.3 i + 0.7 j
- The displacement vector d in component form is d = ( -0.3 , 0.7 ) miles
Answer:768.75N
Explanation:
mass=62.5kg
acceleration=12.3m/s^2
Force=mass x acceleration
Force=62.5 x 12.3
Force=768.75N
Answer:
b) 1.67×10^7 m/s
Explanation:
The solution is attached in the attachment section
The answer is; A
As the ball bounces, the kinetic energy is lost as heat and therefore the initial energy of the ball reduces. The ball, therefore, bounces to a less height with each bounce. As the ball hits the floor, it deforms and reforms again. This compression and decompression including friction between the ball and floor are some of the contributors to the loss of its energy to heat (that also warms it up).