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mixas84 [53]
4 years ago
7

How many phases are in a homogeneous mixture??

Chemistry
2 answers:
Mars2501 [29]4 years ago
7 0
Technically there is only one phase unless you account for a solution where you have a pure liquid with something dissolved in it. Unless you count aqueous as a phase which is just dissolved. Since you are in high school the answer you are looking for is one.  <span />
kvv77 [185]4 years ago
7 0

1, it is all the same because it is homogeneous

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The number of the valence electrons determines the oxidation state i.e. oxidation number e.g. oxygen  has 6 valence electrons the oxidation number is -2 that its need to fill up an octet structure.
6 0
4 years ago
Please help!!!!!!
Valentin [98]

Answer:

E.

Explanation:

Look at change in concentration over time...is it increasing or decreasing? It is increasing right as you can see because it starts at 0 then increases and plataeus. What increases in a reaction, reactant or product? Products increase right cuz your reactants react with each other to make prodcuts.

At start of reaction you have no products (zero) thus this graph starts at 0. At end you have alot of product thus over time the concentration of product increases.

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2 years ago
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cupoosta [38]

Explanation:

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4 0
3 years ago
Read 2 more answers
Please help I’m timed !!!
Rashid [163]

Answer:

b. \% diss =4.4x10^{-2}\%

Explanation:

Hello there!

In this case, given the ionization reaction of HClO as weak acid:

HClO\rightleftharpoons H^++ClO^-

We can write the equilibrium expression as shown below:

Ka=3.5x10^{-8}=\frac{[H^+][ClO^-]}{[HClO]}

In such a way, via the definition of x as the reaction extent, we can write:

3.5x10^{-8}=\frac{x^2}{[HClO]}

As long as Ka<<<<1 so that the x on the bottom can be neglected. Thus, we solve for x as shown below:

x=\sqrt{3.5x10^{-8}*0.18} =\\\\x=7.94x10^{-5}M

And finally the percent dissociation:

\% diss=\frac{x}{[HClO]} *100\%\\\\\% diss=\frac{7.94x10^{-5}M}{0.18}*100\% \\\\\% diss =0.044\%=4.4x10^{-2}\%

Which is choice b.

Best regards!

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3 years ago
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Rom4ik [11]
B) Cu + CaCl2
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6 0
4 years ago
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