Answer:
1.274.
Explanation:
- Thomas Graham found that, at a constant temperature and pressure the rates of effusion of various gases are inversely proportional to the square root of their masses.
<em>∨ ∝ 1/√M.</em>
where, ∨ is the rate of diffusion of the gas.
M is the molar mass of the gas.
<em>∨₁/∨₂ = √(M₂/M₁)</em>
∨₁ is the rate of effusion of the methane.
∨₂ is the rate of effusion of acetylene gas.
M₁ is the molar mass of methane (M₁ = 16.0 g/mol).
M₂ is the molar mass of acetylene (M₂ = 26.0 g/mol).
<em>∴ The rate of effusion of methane, CH₄, relative to the rate of effusion of acetylene, C₂H₂ = ∨₁/∨₂ = √(M₂/M₁) </em>= √(26.0 g/mol)/(16.0 g/mol) = <em>1.274.</em>
Answer:
The elements which are in the group
Is there any answer choices?, Im very confused on what to answer
Answer:
D. concentration, as the concentrations of reactants and products remain unchanged after equilibrium is reached.
Explanation:
I put it for the test and i got right hehe
