All categories

2 years ago

How many phases are in a homogeneous mixture??

2 answers:

7 0

Technically there is only one phase unless you account for a solution where you have a pure liquid with something dissolved in it. Unless you count aqueous as a phase which is just dissolved. Since you are in high school the answer you are looking for is one.

kvv77 [185]2 years ago

7 0

1, it is all the same because it is homogeneous

You might be interested in

(7.6 x 104m) x (1.5 x 107m)

cluponka [151]

Answer:

the answer should 126 859.2 m2

3 0

2 years ago

Read 2 more answers

PLEASE HELP TEST does anyone know the answer???? density question

CaHeK987 [17]

Answer:

The answer is honey.

Explanation:

8 0

2 years ago

Read 2 more answers

The switch is used to ___________ or __________ an electrical circuit. When the switch is on, the circuit is __________ , and wh

Pani-rosa [81]

Answer:

The switch is used to disconnect or connect an electrical circuit. When the switch is on, the circuit is complete, and when the switch is off, the circuit is open. Electrical current exists in the circuit when it is closed, but when it is open, there is no electrical current in the circuit. The switch determines whether the circuit is open and closed.

6 0

2 years ago

Describe how PERIODS and GROUPS are set up on the Periodic Table of Elements.

Oliga [24]

Answer:

Periods are horizontal rows (across) the periodic table, while groups are vertical columns (down) the table. Atomic number increases as you move down a group or across a period.

(Love your pfp btw)

Explanation:

8 0

2 years ago

635 mL of a gas is at a pressure of 8.00 atm. What is the volume of the gas at standard pressure (STP)?

Sveta_85 [38]

The new volume at standard temperature and pressure is 5.08 L.

Explanation:

As per the kinetic theory of gases, the volume occupied by gas molecules will be inversely proportional to the pressure of the gas molecules. This is termed as Boyle's law.

So, pressure∝ $\frac{1}{volume}$

Thus, if two pressure and two volumes are given then,

$P_{1} V_{1} = P_{2} V_{2}\\$

Now, we known the values of P₁ = 8 atm, V₁ = 635 mL, P₂ = 1 atm and V₂ we have to determine. We are considering P₂ = 1 atm, because we have to determine V₂ at standard temperature and pressure. And standard pressure is 1 atm.

$8*635*10^{-3} = 1 *V{2} \\\\V_{2} = \frac{8*635*10^{-3} }{1} = 5.08 L$

Thus, the new volume at standard temperature and pressure is 5.08 L.

5 0

2 years ago