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cluponka [151]
3 years ago
12

When the vapor pressure of water is 0.106 mmHg, determine the reaction quotient for that above equilibrium.

Chemistry
1 answer:
TEA [102]3 years ago
8 0

Answer:

Answer is explained in the explanation section below.

Explanation:

Note: This question is not complete and lacks necessary data to solve. However, I have found a similar question and I will be using its data to solve this question for the sake of understanding and concept.

Solution:

Equilibrium Reaction:

CaO(s) + H2O(g) -->Ca(OH)2(s)    

We need to find the reaction quotient for this question:

Q = \frac{1}{P_{H20} }

Here, only the pressure of the gaseous reactant will be used and here H20 is the only reactant which is gaseous.

And we are given that, vapor pressure of water is = 0.106 mmHg

So,

Now, we need to convert it into atm

so, 1atm = 760 mmHg

0.106 mmHg = 0.106/760 atm

0.106 mmHg = 1.394 x 10^{-4} atm

Plugging in the values in the equation, we get:

Q = \frac{1}{P_{H20} }

Q = \frac{1}{1.394 . 10^{-4} }

Q = 7173.60 atm^{-1}

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leva [86]

Answer:

30.17 × 10²³ atoms

Explanation:

Given data:

Number of moles of lead = 5.01 mol

Number of atoms = ?

Solution:

Avogadro number:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

In given question:

1 mole = 6.022 × 10²³ atoms

5.01 mol × 6.022 × 10²³ atoms / 1 mol

30.17 × 10²³ atoms

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What can be added to a solution to control the pH?
Zanzabum

Answer:

liquid

Explanation:

Adjusting pH in Water

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A sample of an unknown compound with a mass of 0.847 g has the following composition: 50.51 % fluorine and 49.49 % iron. When th
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This is determined because even when the compound is decomposed, due to conservative law of mass, the decomposition process do not affect the amount of matter, so the mass of the elements remain even if they are separated from the original molecule.

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