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3 years ago

When the vapor pressure of water is 0.106 mmHg, determine the reaction quotient for that above equilibrium.

Chemistry

1 answer:

TEA [102]3 years ago

8 0

Answer:

Answer is explained in the explanation section below.

Explanation:

Note: This question is not complete and lacks necessary data to solve. However, I have found a similar question and I will be using its data to solve this question for the sake of understanding and concept.

Solution:

Equilibrium Reaction:

CaO(s) + H2O(g) -->Ca(OH)2(s)

We need to find the reaction quotient for this question:

Q = $\frac{1}{P_{H20} }$

Here, only the pressure of the gaseous reactant will be used and here H20 is the only reactant which is gaseous.

And we are given that, vapor pressure of water is = 0.106 mmHg

So,

Now, we need to convert it into atm

so, 1atm = 760 mmHg

0.106 mmHg = 0.106/760 atm

0.106 mmHg = 1.394 x $10^{-4}$ atm

Plugging in the values in the equation, we get:

Q = $\frac{1}{P_{H20} }$

Q = $\frac{1}{1.394 . 10^{-4} }$

Q = 7173.60 $atm^{-1}$

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number of HBr moles reacted - 0.25 M/ 1000 mL/L x 96.0 mL = 0.024 mol
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The image is not given in the question, it is attached below:

<u>Answer:</u> The excess reactant is NO, the limiting reactant is CO and the products are shown in the image attached below.

<u>Explanation:</u>

In the given image:

Red spheres represent oxygen atoms, blue spheres represent nitrogen atoms and black spheres represent carbon atoms

The combination of 1 black and 2 red spheres will represent carbon dioxide $(CO_2)$ compound

The combination of 2 blue spheres will represent nitrogen molecule $(N_2)$

The combination of 1 blue and 1 red sphere will represent nitrogen monoxide $(NO)$ compound

The combination of 1 black and 1 red sphere will represent nitrogen monoxide $(NO)$ compound

Limiting reagent is defined as the reagent which is completely consumed in the reaction and limits the formation of the product.

Excess reagent is defined as the reagent which is left behind after the completion of the reaction.

We are given:

Given moles of NO = 6 moles

Given moles of CO = 4 moles

For the given chemical equation:

$2NO(g)+2CO(g)\rightarrow N_2(g)+2CO_2(g)$

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If 2 moles of CO reacts with 2 moles of NO

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As the given amount of NO is more than the required amount. Thus, it is present in excess and is considered as an excess reagent.

Thus, CO is considered a limiting reagent because it limits the formation of the product.

Hence, the excess reactant is NO, the limiting reactant is CO and the products are shown in the image attached below.

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