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cluponka [151]
3 years ago
12

When the vapor pressure of water is 0.106 mmHg, determine the reaction quotient for that above equilibrium.

Chemistry
1 answer:
TEA [102]3 years ago
8 0

Answer:

Answer is explained in the explanation section below.

Explanation:

Note: This question is not complete and lacks necessary data to solve. However, I have found a similar question and I will be using its data to solve this question for the sake of understanding and concept.

Solution:

Equilibrium Reaction:

CaO(s) + H2O(g) -->Ca(OH)2(s)    

We need to find the reaction quotient for this question:

Q = \frac{1}{P_{H20} }

Here, only the pressure of the gaseous reactant will be used and here H20 is the only reactant which is gaseous.

And we are given that, vapor pressure of water is = 0.106 mmHg

So,

Now, we need to convert it into atm

so, 1atm = 760 mmHg

0.106 mmHg = 0.106/760 atm

0.106 mmHg = 1.394 x 10^{-4} atm

Plugging in the values in the equation, we get:

Q = \frac{1}{P_{H20} }

Q = \frac{1}{1.394 . 10^{-4} }

Q = 7173.60 atm^{-1}

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Calculate the freezing point of a solution containing 5. 0 grams of kcl and 550. 0 grams of water. the molal-freezing-point-depr
lutik1710 [3]

The freezing point of a solution containing 5. 0 grams of KCl and 550.0 grams of water is  - 0.45°C

Using the equation,

ΔT_{f} = iK_{f}m

where:

ΔT_{f} = change in freezing point (unknown)

i = Van't Hoff factor

K_{f} = freezing point depression constant

m = molal concentration of the solution

Molality is expressed as the number of moles of the solute per kilogram of the solvent.

Molal concentration is as follows;

MM KCl = 74.55 g/mol

molal concentration = \frac{5.0g*\frac{1mol}{74.55g} }{550.0g*\frac{1kg}{1000g} }

molal concentration = 0.1219m

Now, putting in the values to the equtaion ΔT_{f} = iK_{f}m we get,

ΔT_{f} = 2 × 1.86 × 0.1219

ΔT_{f} = 0.4536°C

So, ΔT_{f} of solution is,

ΔT_{f_{solution} } = 0.00°C - 0.45°C

ΔT_{f_{solution} } =  - 0.45°C

Therefore,freezing point of a solution containing 5. 0 grams of KCl and 550.0 grams of water is  - 0.45°C

Learn more about freezing point here;

brainly.com/question/3121416

#SPJ4

7 0
1 year ago
“True or False”
Sliva [168]
True, I’m sorry if I’m wrong
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2 years ago
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