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dybincka [34]
3 years ago
6

A 5.0-ohm resistor, a 10.0-ohm resistor, and a 15.0-ohm resistor are connected in parallel with a battery. The current through t

he 5.0-ohm resistor is 2.4 amperes. Calculate the amount of electrical energy expended in the 5.0-ohm resistor in 2.0 minutes.
Physics
1 answer:
Kaylis [27]3 years ago
8 0

Answer:

E = 3456 J

Explanation:

The electrical energy expended in a resistor can be easily calculated by using the following formula:

E = Pt

where,

E = Energy Expended = ?

I = current through 5 ohm resistor = 2.4 A

R = Resistance = 5 ohms

P = Electrical Power = VI

Since,

V = IR (Ohm's Law)

Therefore,

P = (IR)(I) = I²R = (2.4 A)²(5 ohms) = 28.8 Watt

t = time taken = (2 min)(60 s/1 min) = 120 s

Therefore,

E = (28.8 Watt)(120 s)

<u>E = 3456 J</u>

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Read 2 more answers
A comet is traveling through space with speed 3.01 ✕ 104 m/s when it encounters an asteroid that was at rest. The comet and the
Tcecarenko [31]

Answer: 8.493(10)^{-3} m/s

Explanation:

According to the conservation of linear momentum principle, the initial momentum p_{i} (before the collision) must be equal to the final momentum p_{f} (after the collision):

p_{i}=p_{f} (1)

In addition, the initial momentum is:

p_{i}=m_{1}V_{1}+m_{2}V_{2} (2)

Where:

m_{1}=1.71(10)^{14} kg is the mass of the comet

m_{2}=6.06(10)^{20} kg is the mass of the asteroid

V_{1}=3.01(10)^{4} m/s is the velocity of the comet, which is positive

V_{2}=0 m/s is the velocity of the asteroid, since it is at rest

And the final momentum is:

p_{f}=(m_{1}+m_{2})V_{f} (3)

Where:

V_{f} is the final velocity

Then :

m_{1}V_{1}+m_{2}V_{2}=(m_{1}+m_{2})V_{f} (4)

Isolating V_{f}:

V_{f}=\frac{m_{1}V_{1}}{m_{1}+m_{2}} (5)

V_{f}=\frac{(1.71(10)^{14} kg)(3.01(10)^{4} m/s)}{1.71(10)^{14} kg+6.06(10)^{20} kg}

Finally:

V_{f}=8.493(10)^{-3} m/s This is the final velocity, which is also in the positive direction.

8 0
3 years ago
A ball with a mass of 275 g is dropped from rest, hits the floor, and re-bounds upward. If the ball hits the floor with a speed
disa [49]

Answer:

a) \Delta p = 1.350\,\frac{kg\cdot m}{s}, b) \Delta p' = -0.454\,\frac{kg\cdot m}{s}, c) D. The magnitud of the change in the ball's momentum.

Explanation:

a) The magnitude of the change in the ball's momentum is:

\Delta p = (0.275\,kg)\cdot \left[\left(1.63\,\frac{m}{s} \right)-\left(-3.28\,\frac{m}{s} \right)\right]

\Delta p = 1.350\,\frac{kg\cdot m}{s}

b) The change in the magnitude of the ball's momentum:

\Delta p' = (0.275\,kg)\cdot \left[(1.63\,\frac{m}{s} )-(3.28\,\frac{m}{s} ) \right]

\Delta p' = -0.454\,\frac{kg\cdot m}{s}

c) The magnitude of the change in the ball's momentum is more directly related to the net force acting on the ball, as it measures the effect of the force on change in ball's motion at measured time according to the Impact Theorem. So, the right answer is option D.

3 0
3 years ago
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