Answer:
The peak emf generated by the coil is 418.3 mV
Explanation:
Given;
number of turns, N = 980 turns
diameter, d = 11 cm = 0.11 m
magnetic field, B = 5 x 10⁻⁵ T
time, t = 7 ms = 7 x 10⁻³ s
peak emf, V₀ = ?
V₀ = NABω
Where;
N is the number of turns
A is the area
B is the magnetic field strength
ω is the angular velocity
V₀ = NABω and ω = 2πf = 2π/t
V₀ = NAB2π/t
A = πd²/4
V₀ = N x (πd²/4) x B x (2π/t)
V₀ = 980 x (π x 0.11²/4) x 5 x 10⁻⁵ x (2π/0.007)
V₀ = 980 x 0.00951 x 5 x 10⁻⁵ x 897.71
V₀ = 0.4183 V = 418.3 mV
The peak emf generated by the coil is 418.3 mV
