If a surplus exists, then quantity demanded is less than quantity supplied, there will be pressure on price fall toward equilibrium.
When the quantity of supply of goods matches the demands for goods, it is called the equilibrium price. The market is said to be in a state of equilibrium when the main situation is in the phase of consolidation. Then, it can be concluded that demand and supply are comparatively equal. Equilibrium price examples are discussed below as well.
We can find the equilibrium price by using the equilibrium price formula. These are the steps:
- Calculate the supply function,
- Calculate the demand function,
- Set the equal amount of quantities for the demand and supply,
- Put this equilibrium price into a supply function,
- Check the result by putting the equilibrium price into the demand function.
A surplus implies the government has extra funds. These funds can be used toward public debt, to start new events, social service or Medicare service and also in reducing interest rates which can help the economy.
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Answer:
1.312 x 10⁻¹² J/nucleon
Explanation:
mass of ¹³⁶Ba = 135.905 amu
¹³⁶Ba contain 56 proton and 80 neutron
mass of proton = 1.00728 amu
mass of neutron = 1.00867 amu
mass of ¹³⁶Ba = 56 x 1.00728 amu + 80 x 1.00867 amu
= 137.10128 amu
mass defect = 137.10128 - 135.905
= 1.19628 amu
mass defect = 1.19628 x 1.66 x 10⁻²⁷ Kg
= 1.9858 x 10⁻²⁷ Kg
speed of light = 3 x 10⁸ m/s
binding energy,
E = mass defect x c²
E = 1.9858 x 10⁻²⁷ x (3 x 10⁸)²
E = 17.87 x 10⁻¹¹ J/atom
now,
binding energy per nucleon =
= 0.1312 x 10⁻¹¹ J/nucleon
= 1.312 x 10⁻¹² J/nucleon
Answer:
the spring constant is -89.2857 n/m
Explanation:
The computation of the spring constant is shown below:
As we know that
Force in newtons = Spring constant × amount of extension
F = -k × x
where
F = 25 N
And, x = 0.280m
So, the spring constant would 2
= 25N ÷ 0.280 m
= -89.2857 n/m
Hence the spring constant is -89.2857 n/m
Voltage is increased, i think.
Answer:
ΔS total ≥ 0 (ΔS total = 0 if the process is carried out reversibly in the surroundings)
Explanation:
Assuming that the entropy change in the aluminium bar is due to heat exchange with the surroundings ( the lake) , then the entropy change of the aluminium bar is, according to the second law of thermodynamics, :
ΔS al ≥ ∫dQ/T
if the heat transfer is carried out reversibly
ΔS al =∫dQ/T
in the surroundings
ΔS surr ≥ -∫dQ/T = -ΔS al → ΔS surr ≥ -ΔS al = - (-1238 J/K) = 1238 J/K
the total entropy change will be
ΔS total = ΔS al + ΔS surr
ΔS total ≥ ΔS al + (-ΔS al) =
ΔS total ≥ 0
the total entropy change will be ΔS total = 0 if the process is carried out reversibly in the surroundings
