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Brut [27]
3 years ago
14

student plans to isolate chlorophyll, mix it in a solution of carbon dioxide and water, and then shine light on the mixture. Do

you predict glucose will be produced inside the mixture
Chemistry
1 answer:
Inga [223]3 years ago
7 0

Answer:

No

Explanation:

<u>In order for glucose to be produced inside the mixture, photosynthesis has to take place</u>. The photosynthetic process requires a series of steps within an organelle called the <u>chloroplast</u>. The chloroplast contains the chlorophyll and other enzymes that are necessary for photosynthesis.

<em>Once the chlorophyll is isolated, it becomes separated from the enzymes necessary for the completion of photosynthesis, and the process is truncated. </em>When light is shined on the mixture, the majority would instead be lost as heat while some cause the chlorophyll molecules to glow.

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Write the complete ionic equation for the reaction that takes place when aqueous solutions of strontium hydroxide and lithium ph
Nesterboy [21]

Answer : The net ionic equation will be,

3Sr^{2+}(aq)+2PO_4^{3-}(aq)\rightarrow Sr_3(PO_4)_2(s)

Explanation :

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

The given balanced ionic equation will be,

3Sr(OH)_2(aq)+2Li_3​PO_4(aq)\rightarrow 6LiOH(aq)+Sr_3(PO_4)_2(s)

The ionic equation in separated aqueous solution will be,

3Sr^{2+}(aq)+6OH^{-}(aq)+6Li^{+}(aq)+2PO_4^{3-}(aq)\rightarrow Sr_3(PO_4)_2(s)+6Li^+(aq)+6OH^{-}(aq)

In this equation, Li^+\text{ and }OH^- are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

3Sr^{2+}(aq)+2PO_4^{3-}(aq)\rightarrow Sr_3(PO_4)_2(s)

4 0
3 years ago
What are the answers?
IrinaK [193]

For Number 2 It Is The Law Of Conversation Of Mass

Number 3 Atoms Of Each Element

Number 7 Oxygen

Number 5 Single Replacement Reaction

I answered a few of them

6 0
4 years ago
How many mL of water would be displaced by 408 g of lead?
Galina-37 [17]

Answer:

36 mL of water can be displace by the 408 g lead

Explanation:

Given data:

Mass of lead = 408 g

Volume of water displaced by lead = ?

Solution:

The volume of water displace by the lead would be equal to the given volume of lead.

So we will calculate the volume from given mass of lead from density formula.

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Density of lead is 11.36 g/cm³.

d = m/v

11.36 g/cm³ = 408 g/ v

v = 408 g/ 11.36 g/cm³

v =36 cm³

1 cm³  = 1 mL

volume = 36 mL

36 mL of water can be displace by the 408 g lead.

4 0
4 years ago
A mixture of gases at a total pressure of 95 kPa contains N₂, CO₂, and O₂. The partial pressure of the CO₂ is 24 kPa and the par
Zinaida [17]

Answer:

23 kPa = Partial pressure O₂

Explanation:

In a mixture of gases, the sum of partial pressure of each gas that contains the mixture = Total pressure

Total pressure = Partial pressure N₂ + Partial pressure CO₂ + Partial pressure O₂

95 kPa = 48 kPa + 24 kPa + Partial pressure O₂

95 kPa - 48 kPa - 24 kPa = Partial pressure O₂

23 kPa = Partial pressure O₂

7 0
3 years ago
Write and balance the combination reaction for the heating of solid magnesium in the presence of nitrogen gas. In a particular e
Makovka662 [10]

Answer:

The mass of magnesium that has been consumed, was 6.69 g

Explanation:

The reaction is this one:

3Mg (s)  +  N₂(g) →  Mg₃N₂

3 moles of solid magnesium react with 1 mol of nitrogen, to make 1 mol of magnesium nitride.

If 9.27 grams of nitrogen react, we see that ratio is 1:1, so we make 9.27 grams of nitride.

Mass / Molar mass = Moles

9.27 g / 100.9 g/m = 0.092 moles

If we have 0.092 moles of nitride, ratio between Mg is 1:3 so, the rule of three will be:

1 mol of Nitride was produced by 3 moles of Mg (s)

0.092 moles of nitride were produced by, (0.092 .3)/1 = 0.275 moles

Mass og Mg = 24.3 g/m

Molar mass . Moles = Mass

0.275 m . 24.3g/m = 6.69 g

4 0
3 years ago
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