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vovikov84 [41]
3 years ago
5

An aqueous magnesium chloride solution is made by dissolving 7.15 moles of MgCl2 in sufficient water so that the final volume of

the solution is 2.50 L . Calculate the molarity of the MgCl2 solution.
Chemistry
1 answer:
irinina [24]3 years ago
4 0

Answer:

2.86mol/L

Explanation:

Given parameters:

Number of moles of MgCl₂  = 7.15moles

Volume of solution  = 2.50L

Unknown:

Molarity of the MgCl₂ solution = ?

Solution:

The molarity of a solution is the number of moles of solute found in a given volume.

  Molarity  = \frac{number of moles }{volume}  

 Insert the parameters and solve;

   Molarity  = \frac{7.15}{2.5}   = 2.86mol/L

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DiKsa [7]

Answer:

75 ml of 0.1M  base neutralizes 25 ml of 0.1M acid, which means the acid has 0.3 moles/L of H ion

but that means each molecule of the acid has 3 times as many H ions aH ions in a molecule of NaOH

which means the formula for the acid must be H3A and

the value of x in

HxA is 3

Explanation:

75ml of a solutipn of 0.1moL  l-1 NaOH neutralises 25ml of a solution of an acid. The formula of the acid is HxA and the concentration of the acid is 0.1mol l-1. What is the value of x?​

the concentration of both the and the base are the same at 0.1M

the base...NaOH has 0.1 moles/L of OH ion

75 ml of 0.1M  base neutralizes 25 ml of 0.1M acid, which means the acid has 0.3 moles/L of H ion

but that means each molecule of the acid has 3 times as many H ions aH ions in a molecule of NaOH

which means the formula for the acid must be H3A and the value of x in

HxA is 3

6 0
3 years ago
To aid in the prevention of tooth decay, it is recommended that drinking water contains 0.900 ppm fluoride (F-). A) How many g o
Romashka-Z-Leto [24]

Answer:

a) <u>1.740 g</u> of F- must be added to a cylindrical water reservoir

b) Grams of sodium fluoride, NaF, that contain this much fluoride:

3.84 g

Explanation:

Step 1. calculate the volume of the tank:

Volume of cylinder =

\pi  r^{2}h ,

Here r = radius of the cylinder = d/2

h = depth = 21.80m

r=\frac{d}{2}

=\frac{3.36x10^{2}}{2}

= 168 m

Volume =

=\frac{22\times 168^{2}\times 21.80}{7}

=1.93\times 10^{6} m^{3}

2.Convert ppm to g/m3 and Solve for mass of F-

1ppm = 1g/m^{3}

0.9ppm = 0.9g/m^{3}

Because both ppm and g/m3 are same quantity .

g/m^{3} =\frac{mass\ of\ F-(g)}{Volume\ m^{3}}\times 10^{6}

0.9 =\frac{mass\ of\ F-}{1.93\times 10^{6} m^{3}}\times 10^{6}

mass\ of\ F- =1.740g

mass of F- required = 1.740 g

3. Apply <u>mole concept </u>to calculate grams of sodium fluoride produced

mass of 1 mole of F2 = 38 g

mass of 1 mole of NaF = 42 g

(from periodic table calculate molar mass)

2Na+F_{2}\rightarrow 2NaF

Here 1 mole of F2 produce = 2 mole of NaF

So,

38 g  of F2 produce = 2 x 42 g of NaF

38 g of F2 produce = 84 g of NaF

1 g of F2 produce = 84/38 g of NaF

1.74 g F2 produce =

\frac {84}{38}\times 1.74

1.74 g F2 produce = 3.84 g of NaF

3.84 g of NaF is produced

3 0
3 years ago
3) In 5 electron group molecules, what is the difference between axial and equatorial positions? Which groups are removed as lon
shusha [124]

The axial positions the bond angle is 120 degrees and in equatorial positions the bond angle is 90 degrees.

Functional groups on central atom gets reduce if lone pairs are added.

Explanation:

The number of lone pairs and base pairs of electrons tells the geometry of the molecule.

VSEPR Theory helps to know the lone pairs and bond pair electrons on the centre atom of the molecule.

Example of molecule containing 5 electron pairs can have four bond pairs and 1 lone pair.

eg: ClF_{3}

the repulsion is shown as

lp-lp> lp-bp>bp-bp

These are in equatorial position because of the repulsion of lone pairs.

It can have 2 lone pairs and 3 bond pairs. eg. XeF_{2}

Lone pairs in this is also in equatorial position as

lp-lp> lp-bp> bp-bp

In axial positions the bond angle is 120 degrees

in equatorial positions the bond angle is 90 degrees, due to the repulsion in  lone pair of electrons.

If 1 lone pair is there it can be replaced by bonding with hydrogen.

If 2 lone pairs are there then bonding with oxygen is there. The covalent bond is formed.

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Answer:

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